python - 将文本文件拆分为带有特殊分隔符行的部分 - python

Question

我有一个这样的输入文件:

This is a text block start
This is the end

And this is another
with more than one line
and another line.

期望的任务是按由一些特殊行分隔的部分读取文件，在这种情况下它是一个空行，例如[出]:

[['This is a text block start', 'This is the end'],
['And this is another','with more than one line', 'and another line.']]

我通过这样做得到了想要的输出:

def per_section(it):
    """ Read a file and yield sections using empty line as delimiter """
    section = []
    for line in it:
        if line.strip('\n'):
            section.append(line)
        else:
            yield ''.join(section)
            section = []
    # yield any remaining lines as a section too
    if section:
        yield ''.join(section)

但是如果特殊行是以#开头的行 e.g.:

# Some comments, maybe the title of the following section
This is a text block start
This is the end
# Some other comments and also the title
And this is another
with more than one line
and another line.

我必须这样做:

def per_section(it):
    """ Read a file and yield sections using empty line as delimiter """
    section = []
    for line in it:
        if line[0] != "#":
            section.append(line)
        else:
            yield ''.join(section)
            section = []
    # yield any remaining lines as a section too
    if section:
        yield ''.join(section)

如果我允许 per_section() 有一个分隔符参数，我可以试试这个:

def per_section(it, delimiter== '\n'):
    """ Read a file and yield sections using empty line as delimiter """
    section = []
    for line in it:
        if line.strip('\n') and delimiter == '\n':
            section.append(line)
        elif delimiter= '\#' and line[0] != "#":
            section.append(line)
        else:
            yield ''.join(section)
            section = []
    # yield any remaining lines as a section too
    if section:
        yield ''.join(section)

但是有没有办法让我不对所有可能的分隔符进行硬编码？

Answer 1

传递谓词怎么样？

def per_section(it, is_delimiter=lambda x: x.isspace()):
    ret = []
    for line in it:
        if is_delimiter(line):
            if ret:
                yield ret  # OR  ''.join(ret)
                ret = []
        else:
            ret.append(line.rstrip())  # OR  ret.append(line)
    if ret:
        yield ret

用法:

with open('/path/to/file.txt') as f:
    sections = list(per_section(f))  # default delimiter

with open('/path/to/file.txt.txt') as f:
    sections = list(per_section(f, lambda line: line.startswith('#'))) # comment