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python - 不可排序的类型 : Vertex() < Vertex()

转载 作者:太空狗 更新时间:2023-10-30 02:43:21 27 4
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我在使用 dijkstra 时遇到了这个错误:TypeError:不可排序的类型:Vertex() < Vertex()

整个错误日志是:

Traceback (most recent call last):
File "C:/Users/Dimitar/PycharmProjects/Dijkstra/Dijkstra.py", line 165, in <module>
dijkstra(g, g.get_vertex('a'))
File "C:/Users/Dimitar/PycharmProjects/Dijkstra/Dijkstra.py", line 101, in dijkstra
heapq.heapify(unvisited_queue)
TypeError: unorderable types: Vertex() < Vertex()

这是我的代码:

import sys


class Vertex:
def __init__(self, node):
self.id = node
self.adjacent = {}
# Set distance to infinity for all nodes
self.distance = sys.maxsize
# Mark all nodes unvisited
self.visited = False
# Predecessor
self.previous = None

def add_neighbor(self, neighbor, weight=0):
self.adjacent[neighbor] = weight

def get_connections(self):
return self.adjacent.keys()

def get_id(self):
return self.id

def get_weight(self, neighbor):
return self.adjacent[neighbor]

def set_distance(self, dist):
self.distance = dist

def get_distance(self):
return self.distance

def set_previous(self, prev):
self.previous = prev

def set_visited(self):
self.visited = True

def __str__(self):
return str(self.id) + ' adjacent: ' + str([x.id for x in self.adjacent])


class Graph:
def __init__(self):
self.vert_dict = {}
self.num_vertices = 0

def __iter__(self):
return iter(self.vert_dict.values())

def add_vertex(self, node):
self.num_vertices = self.num_vertices + 1
new_vertex = Vertex(node)
self.vert_dict[node] = new_vertex
return new_vertex

def get_vertex(self, n):
if n in self.vert_dict:
return self.vert_dict[n]
else:
return None

def add_edge(self, frm, to, cost=0):
if frm not in self.vert_dict:
self.add_vertex(frm)
if to not in self.vert_dict:
self.add_vertex(to)

self.vert_dict[frm].add_neighbor(self.vert_dict[to], cost)
self.vert_dict[to].add_neighbor(self.vert_dict[frm], cost)

def get_vertices(self):
return self.vert_dict.keys()

def set_previous(self, current):
self.previous = current

def get_previous(self, current):
return self.previous


def shortest(v, path):
''' make shortest path from v.previous'''
if v.previous:
path.append(v.previous.get_id())
shortest(v.previous, path)
return


import heapq


# noinspection PyArgumentList
def dijkstra(aGraph, start):
print('''Dijkstra's shortest path''')
# Set the distance for the start node to zero
start.set_distance(0)

# Put tuple pair into the priority queue
unvisited_queue = [(v.get_distance(), v) for v in aGraph]
heapq.heapify(unvisited_queue)

while len(unvisited_queue):
# Pops a vertex with the smallest distance
uv = heapq.heappop(unvisited_queue)
current = uv[1]
current.set_visited()

for next in current.adjacent:
# if visited, skip
if next.visited:
continue
new_dist = current.get_distance() + current.get_weight(next)

if new_dist < next.get_distance():
next.set_distance(new_dist)
next.set_previous(current)
print
('updated : current = %s next = %s new_dist = %s' \
% (current.get_id(), next.get_id(), next.get_distance()))
else:
print
('not updated : current = %s next = %s new_dist = %s' \
% (current.get_id(), next.get_id(), next.get_distance()))

# Rebuild heap
# 1. Pop every item
while len(unvisited_queue):
heapq.heappop(unvisited_queue)
# 2. Put all vertices not visited into the queue
unvisited_queue = [(v.get_distance(), v) for v in aGraph if not v.visited]
heapq.heapify(unvisited_queue)


if __name__ == '__main__':

g = Graph()

g.add_vertex('a')
g.add_vertex('b')
g.add_vertex('c')
g.add_vertex('d')
g.add_vertex('e')
g.add_vertex('f')

g.add_edge('a', 'b', 7)
g.add_edge('a', 'c', 9)
g.add_edge('a', 'f', 14)
g.add_edge('b', 'c', 10)
g.add_edge('b', 'd', 15)
g.add_edge('c', 'd', 11)
g.add_edge('c', 'f', 2)
g.add_edge('d', 'e', 6)
g.add_edge('e', 'f', 9)

print
('Graph data:')
for v in g:
for w in v.get_connections():
vid = v.get_id()
wid = w.get_id()
print
('( %s , %s, %3d)' % ( vid, wid, v.get_weight(w)))

dijkstra(g, g.get_vertex('a'))

target = g.get_vertex('e')
path = [target.get_id()]
shortest(target, path)
print('The shortest path : %s' % (path[::-1]))

有人能解释一下为什么会出现这种错误吗?我是一个自学者,我将不胜感激。

导致错误的代码行是:heapq.heapify(unvisited_queue)

提前感谢所有对此主题发表评论的人。

最好的,迪米塔尔

最佳答案

自定义类型不会隐式定义其实例之间的顺序:

>>> v1 = Vertex(1)
>>> v2 = Vertex(2)
>>> v1 < v2
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unorderable types: Vertex() < Vertex()

你需要告诉 python 如何比较你的顶点。您需要实现 rich comparison这样做的方法。自 heapify需要 < ,你必须至少实现 __lt__ .

您还可以查看 @total_ordering 装饰器以避免实现所有这些。

类似的东西:

from functools import total_ordering

@total_ordering
class Vertex:
# Your current class code

def __eq__(self, other):
if isinstance(other, self.__class__):
return self.distance == other.distance
return NotImplemented

def __lt__(self, other):
if isinstance(other, self.__class__):
return self.distance < other.distance
return NotImplemented

如果您需要将该类用作字典键,则需要添加 __hash__方法。大概是这样的:

    def __hash__(self):
return id(self)

关于python - 不可排序的类型 : Vertex() < Vertex(),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33680224/

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