python - python 请求中的 curl 语句 `--form input=@./thefile.pdf`

Question

我有一个 curl 声明，如下所示，取自 link :

curl -v -include --form input=@./thefile.pdf localhost:8080/processFulltextDocument

我正在尝试使用 Requests 在 Python 中复制上述语句，因此我使用了以下代码

    import requests
    Data = {'input': './samp.pdf'}
    url='http://127.0.0.1:8080/processFulltextDocument'
    r = requests.post(url,data=Data)
    print r.text

但是，我收到 415 错误。我做错了什么？

编辑 curl 语句的标题如下:

curl -v -include --form input=@./samp.pdf 127.0.0.1:8080/processFulltextDocument

* Couldn't find host 127.0.0.1 in the .netrc file; using defaults
* Hostname was NOT found in DNS cache
*   Trying 127.0.0.1...
* Connected to 127.0.0.1 (127.0.0.1) port 8080 (#0)
> POST /processFulltextDocument HTTP/1.1
> User-Agent: curl/7.35.0
> Host: 127.0.0.1:8080
> Accept: */*
> Content-Length: 549488
> Expect: 100-continue
> Content-Type: multipart/form-data; boundary=------------------------df1c59f42e57cbf4
> 
< HTTP/1.1 100 Continue
HTTP/1.1 100 Continue

Answer 1

要发送“multipart/form-data”POST http 请求，请使用files 参数:

#!/usr/bin/env python
import requests  # $ pip install requests

r = requests.post('http://127.0.0.1:8080/processFulltextDocument',
                  files=dict(input=open('samp.pdf', 'rb')))
print(r.text) # print response

参见 POST a Multipart-Encoded File .