python - AES 加密中的 IV must be 16 bytes long 错误

Question

我正在使用 pycrypto AES加密模块。并使用文档我写下了下面的函数，但它总是会给出错误 IV must be 16 bytes long 但我使用的是 16 byte long IV。

def aes_encrypt(plaintext):
    """
    """
    key = **my key comes here**
    iv = binascii.hexlify(os.urandom(16)) # even used without binascii.hexlify)

    aes_mode = AES.MODE_CBC

    obj = AES.new(key, aes_mode, iv)

    ciphertext = obj.encrypt(plaintext)
    return ciphertext

Answer 1

使用这个:

from Crypto.Cipher import AES 
import binascii,os

def aes_encrypt(plaintext):
    key = "00112233445566778899aabbccddeeff"
    iv = os.urandom(16)
    aes_mode = AES.MODE_CBC
    obj = AES.new(key, aes_mode, iv)
    ciphertext = obj.encrypt(plaintext)
    return ciphertext

工作如下:

>>> aes_encrypt("TestTestTestTest")
'r_\x18\xaa\xac\x9c\xdb\x18n\xc1\xa4\x98\xa6sm\xd3'
>>> 

这就是区别:

>>> iv =  binascii.hexlify(os.urandom(16))
>>> iv
'9eae3db51f96e53f94dff9c699e9e849'
>>> len(iv)
32
>>> iv = os.urandom(16)
>>> iv
'\x16fdw\x9c\xe54]\xc2\x12!\x95\xd7zF\t'
>>> len(iv)
16
>>>