python - Django 如何使用模板标签拆分字符串

Question

你好，我想知道如何拆分字典值字符串

这是我的爬虫，它返回的字典数据看起来像

data = {
    {0:'http://..., product name, product price'},
    {1:'http://...2, product name2, product price2'},
    {N:'http://...2, product name2, product price n'}
}

我想用逗号分割这些数据 喜欢，

for value in data.values():
     href, product_name, product_price = str(value).split(",")

在 Django 中

这是我的crawler.py

import requests
from urllib import parse
from bs4 import BeautifulSoup


def spider(item_name):
    url_item_name = parse.quote(item_name.encode('euc-kr'))

    url = 'http://search.11st.co.kr/SearchPrdAction.tmall?method=getTotalSearchSeller&isGnb=Y&prdType=&category=&cmd=&pageSize=&lCtgrNo=&mCtgrNo=&sCtgrNo=&dCtgrNo=&fromACK=recent&semanticFromGNB=&gnbTag=TO&schFrom=&schFrom=&ID=&ctgrNo=&srCtgrNo=&keyword=&adUrl=&adKwdTrcNo=&adPrdNo=&targetTab=T&kwd=' + url_item_name
    resp = requests.get(url)
    resp.raise_for_status()

    resp.encoding='euc-kr'
    plain_text = resp.text

    soup = BeautifulSoup(plain_text, 'lxml')
    mytag = soup.find_all(True, {"class": ["sale_price", "list_info"]})
    #for link in soup.select('div.list_info p.info_tit a') :
    data = {}
    count = -1;
    for link in mytag:
        if(link.find('a')):
            count+=1
            href = link.find('a').get('href')
            product_name = link.find('a').string
            data[count] = str(href) + ", " + str(product_name)
        else:
            product_price = link.string
            if(product_price):
                data[count] = data[count] +", " + str(product_price)

    for value in data.values():
        print(value)
    resp.close()

    return data

这是我的看法

def post_shop_list(request):
    posts = spider("product name")
    return render(request, 'blog/post_list.html',{'posts' : posts})

这是我的 post_list.html

{% for key, value in posts.items %}
    <div>
        <td>{{key}}</td>
        <p>product name :{{value}}</p>
        <h1><a href=href> </a></h1>
        <p>{{ product_price|linebreaksbr}}</p>
    </div>
{% endfor %}

谢谢..!!

Answer 1

创建自定义 template filter

from django import template

register = template.Library()

@register.filter(name='split')
def split(value, key):
  """
    Returns the value turned into a list.
  """
  return value.split(key)

在 Django 模板中你可以像这样使用它。

# assuming value = "url, product_name, product_price"
# and you have always these three comma separated items in sequence
{% for key, value in posts.items %}
   <tr>
      {% with value|split:"," as details %}
         {% for p in details %}
            <td>{{ p }}</td>
         {% endfor %}
      {% endwith %} 
   </tr>    
{% endfor %}

更新

您还必须在 libraries 关键字的 TEMPLATE 列表中输入您的标记文件。

TEMPLATES = [
    {
        'BACKEND': 'django.template.backends.django.DjangoTemplates',
        'DIRS': [
            str(APPS_DIR.path('templates')),
        ],
        'OPTIONS': {

            'loaders': [
                ...
            ],

            'context_processors': [
                ...
            ],
            'libraries':{
               # make your file entry here.
               'filter_tags': 'app.templatetags.filter',
            }
        },
    },
]

然后将此标记加载到您要使用 split 过滤器的 html 文件顶部

{% load filter_tags %}