python - 根据条件拆分单词的字母，并返回列表(Python)

Question

vowels = "aeiou"
consonants = "bcdfghjklmnpqrstvwxyz"

我正在尝试创建一个函数，它只返回列表中后跟元音的常量。

例如:

f("therapist")
>>>["he", "ra", "pi"]
f("apple")
>>>["le"]

所以只有当元音跟在辅音后面时，它才会在列表中同时返回辅音和元音。

我想这应该是这样的:

def f(word):
  for consonant in word:
    for vowel in word:

但我不知道如何处理顺序并测试元音是否在辅音之后。提前致谢

Answer 1

您可以使用起始索引为 1 的枚举，检查当前元素是否为辅音字母以及下一个字符 word[i] 是否为元音字母。

def f(word):
    vowels = {"a", "e", "i", "o", "u"}
    consonants = {'t', 'b', 'm', 'h', 'y', 'w', 'z', 'p', 'v', 'd', 'g', 'k', 'j', 'n', 'r', 'q', 'x', 'c', 's','f', 'l'}        
    return [ele + word[i] for i, ele in enumerate(word[:-1], 1)
            if word[i] in vowels and ele in consonants ]

或者使用循环跟踪最后一个字符并进行比较:

def f(word):
    vowels = {"a", "e", "i", "o", "u"}
    consonants = {'t', 'b', 'm', 'h', 'y', 'w', 'z', 'p', 'v', 'd', 'g', 'k', 'j', 'n', 'r', 'q', 'x', 'c', 's','f', 'l'}       
    pairs = []
    it = iter(word)
    # get first char
    prev = next(it,"")
    # iterate over the rest starting at the second char
    for ch in it:
        # compare prev and current
        if prev in consonants and ch in vowels:
            pairs.append(prev + ch)
        # update prev 
        prev = ch
    return pairs