python 2.7 : making a dictionary object from a specially-formatted list object

Question

我有一个列表类型的对象，如:

     f = [77.0, 'USD', 77.95, 
     103.9549, 'EUR', 107.3634,
     128.1884, 'GBP', 132.3915,
     0.7477, 'JPY', 0.777]

我想创建一个如下的字典:

d = 
{'EUR': [103.9549, 107.3634],
'GBP': [128.1884, 132.3915],
'JPY': [0.7477, 0.777],
'USD': [77.0, 77.95]}

我尝试利用这些答案 Convert a list to a dictionary in Python , 和 Make dictionary from list with python .

但是，找不到正确的方法。

到目前为止，我的解决方案是:

cs = [str(x) for x in f if type(x) in [str, unicode]]
vs = [float(x) for x in f if type(x) in [int, float]]
d =  dict(zip(cs, [[vs[i],vs[i+1]] for i in range(0,len(vs),2)]))

但是，什么才是聪明的单行代码？

Answer 1

怎么样:

In [5]: {f[i+1]: [f[i], f[i+2]] for i in range(0, len(f), 3)}
Out[5]: 
{'EUR': [103.9549, 107.3634],
 'GBP': [128.1884, 132.3915],
 'JPY': [0.7477, 0.777],
 'USD': [77.0, 77.95]}