python，十六进制值转换为字符串/整数

Question

我正在研究如何获取十六进制值，并将它们转换为字符串或整数。示例:

>>> a = b'\x91\x44\x77\x65\x92'
>>> b = b'\x44\x45\x41\x44\x42\x45\x45\x46'
>>> a
>>> �Dwe�
>>> b
>>> 'DEADBEEF'

a 和 b 的预期结果:

>>> 9144776592
>>> '4445414442454546'

谢谢。

Answer 1

>>> a = b'\x91\x44\x77\x65\x92'
>>> a.encode("hex")
'9144776592'
>>> b.encode('hex')
'4445414442454546'

请注意，使用 encode('hex') 不是很好 - 这是一个 explanation为什么:

The way you use the hex codec worked in Python 2 because you can call encode() on 8-bit strings in Python 2, ie you can encode something that is already encoded. That doesn't make sense. encode() is for encoding Unicode strings into 8-bit strings, not for encoding 8-bit strings as 8-bit strings.

In Python 3 you can't call encode() on 8-bit strings anymore, so the hex codec became pointless and was removed.

使用 binascii更简单更好，它是为二进制和 ascii 之间的转换而设计的，它适用于 python 2 和 3:

>>> import binascii
>>> binascii.hexlify(b'\x91\x44\x77\x65\x92')
b'9144776592'