Python:尝试检查有效的电话号码

Question

我正在尝试编写一个程序，它接受格式为 XXX-XXX-XXXX 的电话号码，并将条目中的任何字母转换为相应的号码。

现在我有了这个，如果开始时不正确，它将允许您重新输入正确的数字，然后它会翻译输入的原始数字。我该如何解决这个问题？

def main():
    phone_number= input('Please enter a phone number in the format XXX-XXX-XXXX: ')
    validNumber(phone_number)
    translateNumber(phone_number)

def validNumber(phone_number):
for i,c in enumerate(phone_number):
    if i in [3,7]:
        if c != '-':
            phone_number=input('Please enter a valid phone number: ')
        return phone_number
    elif not c.isalnum():
        phone_number=input('Please enter a valid phone number: ')
        return phone_number
return phone_number


def translateNumber(phone_number):
    s=""
    for char in phone_number:
        if char is '1':
            x1='1'
            s= s + x1
        elif char is '-':
            x2='-'
            s= s + x2
        elif char in 'ABCabc':
            x3='2'
            s= s + x3
        elif char in 'DEFdef':
            x4='3'
            s= s + x4
        elif char in 'GHIghi':
            x5='4'
            s= s + x5
        elif char in 'JKLjkl':
            x6='5'
            s= s + x6
        elif char in 'MNOmno':
            x7='6'
            s= s + x7
        elif char in 'PQRSpqrs':
            x8='7'
            s= s + x8
        elif char in 'TUVtuv':
            x9='8'
            s= s + x9
        elif char in 'WXYZwxyz':
            x10='9'
            s= s + x10
    print(s)

Answer 1

import re

def validNumber(phone_nuber):
    pattern = re.compile("^[\dA-Z]{3}-[\dA-Z]{3}-[\dA-Z]{4}$", re.IGNORECASE)
    return pattern.match(phone_nuber) is not None