python - 在 Python 中递归地转换字典

Question

这是一本字典:

data = {
    'a': {
        'b': {
            'c': {
                'd': {
                    'e': {
                        'f': 1,
                        'g': 50,
                        'h': [1, 2, 4],
                        'i': 3,
                        'j': [7, 9, 6],
                        'k': [
                            [('x', 'abc')],
                            [('y', 'qwe')],
                            [('z', 'zxc')]
                        ]
                    }
                }
            }
        }
    }
}

我的目标是尽可能找到值并将其转换为字典:

data = {
    'a': {
        'b': {
            'c': {
                'd': {
                    'e': {
                        'f': 1,
                        'g': 50,
                        'h': [1, 2, 4],
                        'i': 3,
                        'j': [7, 9, 6],
                        'k': [{
                            'x': 'abc'
                        }, {
                            'y': 'qwe'
                        }, {
                            'z': 'zxc'
                        }]
                    }
                }
            }
        }
    }
}

我认为这可以使用递归来完成，我什至写了一个，但它不起作用。

def f(d):
  for key, value in d.iteritems():
    if type(d[key]) is dict:
      f(d)

    try:
      d[key] = dict(d[key])
    except:
      if type(d[key]) is list:
        for i in d[key]:
          try:
            d[key][i] = dict(d[key][i])
          except:
            pass

  return d

错误:

RecursionError: maximum recursion depth exceeded while calling a Python object

如何让它发挥作用？

如果你能提供一个不用递归的解决方案，我也很乐意得到它。

Answer 1

你的程序中有一堆错误，让我们检查它们并提出一个工作版本。

def f(d):
  for key, value in d.iteritems():
    if type(d[key]) is dict:
      f(d)                        # You should call d[key] instead 
    try:
      d[key] = dict(d[key])       # Never assign an object back to the one you are iterating over, create a new object instead.
    except:
      if type(d[key]) is list:
        for i in d[key]:
          try:
            d[key][i] = dict(d[key][i])  # This doesn't work, can't convert a tuple/list this way.
          except:
            pass

  return d

这是带有两个递归函数的代码的更正版本。一个用于列表，另一个用于字典。

def f1(value):
  e = []
  for val in value:
    if type(val) is list:
      e += f1(val)               # Append list to current list
    elif type(val) is tuple:
      e.append({val[0]: val[1]}) # Convert tuple to dictionary
    else:
      e.append(val)              # Append normal list values normally
  return e

def f(d, e  = {}):
  for key, value in d.iteritems():
    if type(value) is dict:
      e[key] = f(value, {})     # Recurse for dictionaries
    elif type(value) is list:
      e[key] = f1(value)        # Call the other recursive function for list
    else:
      e[key] = value            # Otherwise like strings and ints just append
  return e

在这里测试:https://repl.it/LDKn/0