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python - 我如何像在 Illustrator 中一样在 python 中格式化文本?

转载 作者:太空狗 更新时间:2023-10-30 01:23:24 24 4
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我希望实现几个功能来改善我程序的输出。我想将一列文本的背景设置为某种颜色,这样更清楚的是列属于一起。

一图胜千言:我想转换这个:

Pos.  :123456789012345
Name. :ABCDEFGHIJKLMNO
Str. :SOMESTRINGSOMET <---- indented by half a row, Column number superscripted
Str. :SOM SOMET
Str. :SOMESTRIN ET

为此:

example

我如何使用 python 做到这一点?是否有允许我这样做的框架?我将其转换为 latex ,但是我无法使上标数字起作用。它们需要在文本之上,但不能充当角色,因为图片的列之间存在关系。

Example: A is at position 1. It has as Properties S and O, thats why it is on top of those two and that is why there is an indent of half a character. S has the superscript 170, T has the superscript 185.

特别困难的还有 Str 部分移动半个字符的部分。我想有一个例子将其集成到我的程序中。

最佳答案

有可能想出棘手的解决方案,考虑单间距字体,这可能会解决您的问题。但他们只是在等待失败。您帖子中的灰色列可以完全按照您的图中添加,但我选择不让它改变字母中的颜色(仅仅是因为我发现这样更易读)。

这里有一些可能的 PIL:

enter image description here

稍微改变一下字体:

enter image description here

接下来是更“严重”的字体变化,所有这些都是用代码原样产生的。

enter image description here enter image description here

接下来是生成这些图形的代码。我并没有真正把它做得很好,它可以在很多方面得到改进。将此作为您需要做的事情的示例,也许可以为您的问题找到解决方案。要使用任何类型的字体,您都需要一个实际的排版系统,例如 LaTeX。

import sys
import Image, ImageDraw, ImageFont


# Assumption: some other piece of code separates the data in the following
# format.
line1 = [("Pos. :", 0), ("123456789012345", 0)]
line2 = [("Name. :", 0), ("ABCDEFGHIJKLMNO", 0)]
line3 = [("Str. ", 0), (":", -0.5), ("SOMESTRINGSOMEST", -0.5)]
line4 = [("Wave 1:", 0), ("_XXXX_X____X_X_", 0)]
line5 = [("Wave 2:", 0), ("__XX_XXX_X__X_X", 0)]
line_data = [line1, line2, line3, line4, line5]
# Texts to draw over the last element, in specific positions,
# of lines present in line_data.
subscript = {
2: { # Meaning: third item in line_data
0: "170", # Meaning: draw "170" over the first char
len(line3[-1][0]) - 1: "185", # Draw "185" over the last char
7: "180", # Meaning: draw "180" over the eight char
},
4: {5: "hi"},
3: {6: "ops"}
}

# If the following fonts are not mono spaced, you are going to suffer.
#
# Normal font.
font = ImageFont.truetype('FreeMono.ttf', 40)
# Font for subscript.
font_tiny = ImageFont.truetype('FreeMono.ttf', 20)


im = Image.new("RGBA", (1000, 1000), 'white')
draw = ImageDraw.Draw(im)
line_offset = 4
start_y = 6

width_A, height_A = font.getsize('A')
_, height_tiny_A = font_tiny.getsize('A')

# Collect even columns from the last item of list line1.
even_columns = []
x = 0
for i, (text, _) in enumerate(line1):
for j, letter in enumerate(text):
if i == len(line1) - 1 and not j % 2:
even_columns.append(x)
x += width_A

# Write all lines.
width = 0
l_start_y = start_y
for di, data in enumerate(line_data):
x = 0
for i, (text, xoff) in enumerate(data):
for j, letter in enumerate(text):
# Apply x offset.
extra = width_A * xoff
draw.text((x + extra, l_start_y), letter, font=font, fill='black')
x += width_A
width = max(x, width)
l_start_y += height_A + line_offset

# Collect letter positions from the lines that will have subscripts.
letter_pos = {}
for k in subscript:
letter_pos[k] = {}
x = sum(len(text) for text, _ in line_data[k][:-1]) * width_A
text, xoff = line_data[k][-1]
for i in range(len(text)):
extra = width_A * xoff
letter_pos[k][i] = x + extra
x += width_A
# Write all subscripts.
for k, v in subscript.items():
line = line_data[k]
for pos, text in v.items():
x = letter_pos[k][pos]
y = start_y + (line_offset + height_A) * k
y -= height_tiny_A * 0.4 # XXX A poor heuristic that worked here.
draw.text((x, y), text, font=font_tiny, fill='black')
width = max(width, int(x + font_tiny.getsize(text)[0]))

# Draw grey columns.
columns = Image.new(im.mode, im.size, 'white')
mask = Image.new("L", im.size, 'white')
for x in even_columns:
columns.paste((128, 128, 128), (x, line_offset, x + width_A, l_start_y))
mask.paste(164, (x, line_offset, x + width_A, l_start_y), )
im = Image.composite(im, columns, mask)

# Crop and save the resulting image.
im.crop((0, 0, width, l_start_y + 2)).save(sys.argv[1])

关于python - 我如何像在 Illustrator 中一样在 python 中格式化文本?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13704678/

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