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c# - 0xFF 变成 0x3F

转载 作者:太空狗 更新时间:2023-10-30 01:22:17 26 4
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我向串口发送0xFF

结果是 0x3F。

所有其他字节都是正确的。

情况是这样的……

外部盒子将这些字节发送到 PC...

0xFF, 0x0D, 0x00, 0x30, 0x31, 0x53, 0x55, 0x43, 0x43, 0x45, 0x53, 0x53

C# 在缓冲区中产生这个...

0x3F, 0x0D, 0x00, 0x30, 0x31, 0x53, 0x55, 0x43, 0x43, 0x45, 0x53, 0x53

第一个字节缺少前两位。有人以前见过这个吗?

如果这里有一篇文章解释了正在发生的事情,更重要的是为什么,甚至最重要的是,如何修复它,请指给我看。谢谢。

这是代码;我希望我已经了解 StackOverFlow 系统;仍然是这个社区的新人,我的 C# 知识大约只有 1 或 2 个月。

 public static void OurBackGroundSerialPortReceiver(object sender, SerialDataReceivedEventArgs e )
{
//// Item 1, tell the world, particularly the
//// chief dispatch routin, that we are receiving

aUartSemaphoreThatTells.WhatTheUartBackgroundRxIsDoing = (int)aValueWhichIndicatesThat.theUARTisReceivingData;

SerialPort CurrentPort = (SerialPort)sender; //// Int routine gave is this in the arguments

int LastByteInUartBuffer = CurrentPort.ReadBufferSize;
int TheLastByteTheBoxSent = CurrentPort.BytesToRead;
string inputData = CurrentPort.ReadExisting(); //// This is a C# property method of ports

int Dest;
Dest = UartPlaceHolders.RxBufferLeader; //// Will index into buffer for Chief dispatch

int Source; //// Will index into Uart buffer to fish it out
Source = 0; //// therefore, we start at zero

int TopEdge; //// We'll calculate this here once instead of in the loops below
TopEdge = (int)TheSizeOf.OneSecondsWorthOfData; //// This will tell us when to wrap around


if (Dest < UartPlaceHolders.RxBufferTrailer) //// Half the time we'll have wrap-around
{ //// If that's the case, then the trailer > the leader
while (
(Dest < UartPlaceHolders.RxBufferTrailer) //// If we are wrapped, make sure we don't
&& //// overtake either the trailer or
(Dest < TopEdge) //// go over the top edge
&& //// At the same time, make sure that
(Source <= LastByteInUartBuffer) //// we don't fish out more than is there
)
{
UartData.TheImmediateSecondOfData[Dest] = (byte)inputData[Source]; //// Move bytes into buff for chief
Dest = Dest + 1;
Source = Source + 1;
}

if (Source >= LastByteInUartBuffer) //// Have we done all the bytes for this event ?
{ //// Yes, therefore we will update the leader
UartPlaceHolders.RxBufferLeader = Dest; //// This tells us where to start next time

aUartSemaphoreThatTells.WhatTheUartBackgroundRxIsDoing = (int)aValueWhichIndicatesThat.WeHaveReceivedSomeData;

return; //// and we are done
}
//// // // Else no, more bytes so...
else if (Dest >= TopEdge) //// Did we wrap around ?
{ //// Yes, so
Dest = 0; //// wrap around to the start
while ( //// Now we do the same thing again
Dest < UartPlaceHolders.RxBufferTrailer //// C# and windows keep buffers at 4K max,
&& //// so we will wrap only once
Source < LastByteInUartBuffer //// May not even need that other test
) //// This will finish the rest of the bytes
{
UartData.TheImmediateSecondOfData[Dest] = (byte)inputData[Source]; //// There they go
Dest = Dest + 1;
Source = Source + 1;
}

UartPlaceHolders.RxBufferLeader = Dest; //// This tells us where to start next time
return;
}

else //// Dest is neither <, >, nor =, we have logic error
{
ErrorFlags.SerialPortErrorDescription = (int)AnError.ExistsInTheSerialPortBufferPointers;
return;
}

}

if (Dest >= UartPlaceHolders.RxBufferTrailer) //// Now, if the Trailer is ahead of the leader, here we go
{ //// If that's the case, then the trailer > the leader
while (
//(Dest < UartPlaceHolders.RxBufferTrailer) //// This is the first major difference twixt this time & previous...
// && //// ...because This condition is defacto guarateed to be false now
(Dest < TopEdge) //// We still want to stop before we hit the top edge
&& //// At the same time, make sure that we go past...
(Source < LastByteInUartBuffer) //// ...the last byte the Uart gave us
&&
(Source < TheLastByteTheBoxSent)
)
{
UartData.TheImmediateSecondOfData[Dest] = (byte)inputData[Source]; //// Move bytes into buff for chief
Dest = Dest + 1;
Source = Source + 1;
}

if (Source >= LastByteInUartBuffer) //// Have we done all the bytes for this event ?
{ //// Yes, therefore we will update the leader
UartPlaceHolders.RxBufferLeader = Dest; //// This tells us where to start next time
return; //// and we are done
} //// // Else no, we have more bytes to move, so...
else if (Dest >= TopEdge) //// Did we wrap around ?
{ //// Yes, so...
Dest = 0; //// wrap around to the start
while ( //// Now we do the same thing again
Dest < UartPlaceHolders.RxBufferTrailer //// C# and windows keep buffers at 4K max,
&& //// so we will wrap only once
Source < LastByteInUartBuffer
)
{
UartData.TheImmediateSecondOfData[Dest] = (byte)inputData[Source];
Dest = Dest + 1;
Source = Source + 1;
}

UartPlaceHolders.RxBufferLeader = Dest; //// This tells us where to start next time

aUartSemaphoreThatTells.WhatTheUartBackgroundRxIsDoing = (int)aValueWhichIndicatesThat.WeHaveReceivedSomeData;

return;
}

else //// Dest is neither <, >, nor =, we have logic error
{
ErrorFlags.SerialPortErrorDescription = (int)AnError.ExistsInTheSerialPortBufferPointers;
return;
}

}

}

最佳答案

这里是找到答案的地方......

http://msdn.microsoft.com/en-us/library/system.io.ports.serialport.aspx

向下滚动到“阅读”,它将详细说明用于执行此操作的方法,可在此处找到...

http://msdn.microsoft.com/en-us/library/ms143549.aspx

这是暂时解决这个问题的代码(也许是好的)

        SerialPort CurrentPort = (SerialPort)sender;                                //// caller gave us this in the arguments

int TheNumberOfBytes = CurrentPort.BytesToRead; // The system will tell us how large our array should be

byte[] inputData = new byte[TheNumberOfBytes]; // Our array is not that large

int WeReadThisMany = CurrentPort.Read(inputData, 0, TheNumberOfBytes); //// This is a C# property method of ports

希望我在这里的回答是正确的。

无论如何,此方法的最终结果是此方法读取真正的字节,作为字节,由另一端的任何内容发送到串行端口。

关于c# - 0xFF 变成 0x3F,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13980631/

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