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python - 使用 asyncio.wait 在任务异常后重试任务

转载 作者:太空狗 更新时间:2023-10-30 01:18:29 34 4
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我有多个应该同时运行的协同程序,其中一些可能会抛出异常。在这些情况下,协程应该再次运行。我该如何做到这一点?我正在尝试做的最小演示:

import asyncio
import time

t = time.time()


async def c1():
print("finished c1 {}".format(time.time() - t))


async def c2():
await asyncio.sleep(3)
print("finished c2 {}".format(time.time() - t))


called = False


async def c3():
global called
# raises an exception the first time it's called
if not called:
called = True
raise RuntimeError("c3 called the first time")
print("finished c3 {}".format(time.time() - t))


async def run():
pending = {c1(), c2(), c3()}

num_times_called = 0
while pending:
num_times_called += 1
print("{} times called with {} pending tasks: {}".format(num_times_called, len(pending), pending))

finished, pending = await asyncio.wait(pending, return_when=asyncio.FIRST_EXCEPTION)
for task in finished:
if task.exception():
print("{} got an exception {}, retrying".format(task, task.exception()))
pending.add(task)

print("finished {}".format(finished))

print("finished all {}".format(time.time() - t))


asyncio.get_event_loop().run_until_complete(run())

c3()表示某些协程将失败并需要重新运行。演示的问题是已完成的任务已完成并设置了异常,因此当我将其放回待定集时,下一个运行循环会立即退出而不会重新运行 c3()因为它已经完成了。

有没有办法清除任务以便它运行c3()再次?我知道附加到任务的协程实例不能再等待,否则我得到

RuntimeError('cannot reuse already awaited coroutine',)

这意味着我必须手动管理从协程实例到生成它的协程的映射,然后使用 task._coro 检索失败的协程实例- 这样对吗?

最佳答案

编辑:任务本身可能是 map 中的关键,这样更清晰。

async def run():
tasks = {asyncio.ensure_future(c()): c for c in (c1, c2, c3)}
pending = set(tasks.keys())

num_times_called = 0
while pending:
num_times_called += 1
print("{} times called with {} pending tasks: {}".format(num_times_called, len(pending), pending))

finished, pending = await asyncio.wait(pending, return_when=asyncio.FIRST_EXCEPTION)
for task in finished:
if task.exception():
print("{} got an exception {}, retrying".format(task, task.exception()))
coro = tasks[task]
new_task = asyncio.ensure_future(coro())
tasks[new_task] = coro
pending.add(new_task)

print("finished {}".format(finished))

print("finished all {}".format(time.time() - t))

关于python - 使用 asyncio.wait 在任务异常后重试任务,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51679615/

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