python - Scrapy + 飞溅 + ScrapyJS

Question

我正在使用 Splash 2.0.2 + Scrapy 1.0.5 + Scrapyjs 0.1.1，但我仍然无法通过点击渲染 javascript。这是一个示例网址 https://olx.pt/anuncio/loja-nova-com-250m2-garagem-em-box-fechada-para-arrumos-IDyTzAT.html#c49d3d94cf

我仍然看到没有呈现电话号码的页面:

class OlxSpider(scrapy.Spider):
    name = "olx"
    rotate_user_agent = True
    allowed_domains = ["olx.pt"]
    start_urls = [
        "https://olx.pt/imoveis/"
    ]

    def parse(self, response):
        script = """
        function main(splash)
            splash:go(splash.args.url)
            splash:runjs('document.getElementById("contact_methods").getElementsByTagName("span")[1].click();')
            splash:wait(0.5)
            return splash:html()
        end
        """
        for href in response.css('.link.linkWithHash.detailsLink::attr(href)'):
            url = response.urljoin(href.extract())
            yield scrapy.Request(url, callback=self.parse_house_contents, meta={
                'splash': {
                    'args': {'lua_source': script},
                    'endpoint': 'execute',
                }
            })

        for next_page in response.css('.pager .br3.brc8::attr(href)'):
            url = response.urljoin(next_page.extract())
            yield scrapy.Request(url, self.parse)

    def parse_house_contents(self, response):

        import ipdb;ipdb.set_trace()

我怎样才能让它工作？

Answer 1

添加

splash:autoload("https://code.jquery.com/jquery-2.1.3.min.js")

到 Lua 脚本，它会工作。

function main(splash)
    splash:go(splash.args.url)
    splash:autoload("https://code.jquery.com/jquery-2.1.3.min.js")
    splash:runjs('document.getElementById("contact_methods").getElementsByTagName("span")[1].click();')
    splash:wait(0.5)
    return splash:html()
end

.click() 是 JQuery 函数 https://api.jquery.com/click/