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c# - 检测 WPF Canvas 上两个矩形之间的碰撞

转载 作者:太空狗 更新时间:2023-10-30 01:02:12 26 4
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我是编程新手,我刚开始使用 C#。我现在正在尝试制作我的第一款游戏,我决定使用蛇。到目前为止,我一直在努力研究这个问题,但我看到的所有答案都与使用不同方法移动蛇的人有关。

我的程序使用两个 double (lefttop)来存储蛇在 Canvas 上的位置。我的程序还为游戏中的“食物”使用了两个 double ,分别称为 randomFoodSpawnLeftrandomFoodSpawnTop

我的问题是这样的。如何检测两个仅具有 left 和 top 值的矩形对象之间的碰撞?我很困惑。

snakeWindow是窗口,snakeHead是代表蛇的矩形,left是蛇的左值, top 是蛇的最高值。

void timer_Tick(object sender, EventArgs e)
{
double left = Canvas.GetLeft(snakeHead);
double top = Canvas.GetTop(snakeHead);

if (keyUp)
{
top -= 3;
}
else if (keyDown)
{
top += 3;
}
else if (keyLeft)
{
left -= 3;
}

else if (keyRight)
{
left += 3;
}
// These statements see if you have hit the border of the window, default is 1024x765
if (left < 0)
{
left = 0;
gameOver = true;
}
if (top < 0)
{
top = 0;
gameOver = true;
}
if (left > snakeWindow.Width)
{
left = 0;
gameOver = true;
}
if (top > snakeWindow.Height)
{
top = 0;
gameOver = true;
}
// Statements that detect hit collision between the snakeHead and food
//
if (foodEaten == true)
{
spawnFood();
textBlockCurrentScore.Text += 1;
}

// If gameOver were to be true, then the game would have to end. In order to accomplish this I display to the user that the game is over
// and the snakeHead is disabled, and should restart.
if (gameOver == true)
{
keyRight = false;
keyLeft = false;
keyUp = false;
keyDown = false;
top = 0;
left = 0;

textBlockGameOver.Text = "GAME OVER!";
snakeCanvas.Background = Brushes.Blue;
}


Canvas.SetLeft(snakeHead, left);
Canvas.SetTop(snakeHead, top);
}

最佳答案

您可以使用 System.Windows.Rect.IntersectsWith .像这样尝试:

Rect rect1 = new Rect(left1, top1, widht1, height1);
Rect rect2 = new Rect(left2, top2, widht2, height2);

bool intersects = rect1.IntersectsWith(rect2);

当然,你必须检查蛇的头和它的所有部分。

关于c# - 检测 WPF Canvas 上两个矩形之间的碰撞,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34738882/

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