c# - PagedList 在第二页和之后的页面上丢失搜索过滤器

Question

我丢失了第二页和之后的所有数据。第一个结果/页面显示了正确的数据。第二页及之后，没有数据。

我的代码:

public ActionResult Contact(int? pageNumber, string search, string option, string select)
    {
        if (option == "Company")
        {            
            return View(db.CompaniesServers.Where(x => x.Name.Contains(search)).ToList().ToPagedList(pageNumber ?? 1, 2));
        }
        else
        {
            return View(db.CompaniesServers.ToList().ToPagedList(pageNumber ?? 1, 3));
        }
    }

我的观点:

@using PagedList;
@using PagedList.Mvc;

@model IPagedList<WorkingWithData.Models.CompaniesServer>


@using (Html.BeginForm("Contact", "Home", FormMethod.Get))
            {

    <b>
        Search Options: <br />
    </b>@Html.RadioButton("option", "Company") <text>Company Name</text> 
    @Html.TextBox("search", null, new { style = "height:30px" })  <select id="serverList" style="height:33px; font-size:small" class="btn btn-default">
                    <option value="All">Select Server</option>
                    <option value="10.67.21.40">Lam Server 4</option>
                    <option value="10.67.21.47">Lam Server 14</option>
                    <option value="10.67.21.70">Lam Server 12</option>
                </select> <a class="btn btn-default" href="/Home/Contact">Reset</a>    <input type="submit" name="submit" value="Search" class="btn btn-primary" />
                
}

<table class="table">
    <tr>
        <th>
           Address
        </th>
        <th>
           Port
        </th>
        <th>
           Name
        </th>
        <th>
          Environment
        </th>
        <th>
           Active
        </th>
        <th></th>
    </tr>

@foreach (var item in Model) {
    <tr>
        <td>
            @Html.DisplayFor(modelItem => item.Address)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Port)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Name)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Environment)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Active)
        </td>
        <td>
            @Html.ActionLink("Edit", "Edit", new { id=item.Id }) |
            @Html.ActionLink("Details", "Details", new { id=item.Id }) |
            @Html.ActionLink("Delete", "Delete", new { id=item.Id })
        </td>
    </tr>
}

</table>

@Html.PagedListPager(Model, pageNumber => Url.Action("Contact", new
{
    pageNumber
}))

第一页结果返回有效信息。但是当我进入第二页时，什么也没有出现。调试时我的变量返回 null。

我应该尝试停止页面加载吗？虽然是 MVC 的新功能。

Answer 1

我的解决方法是在 Controller 中使用 ViewBag，我不确定如何在您的代码中实现它，但可能会对您有所帮助

查看:

@model IPagedList<MyModel>
    <div class="pagedList">
        @Html.PagedListPager(Model, page => Url.Action("Index", new { page, search = ViewBag.search }),
       PagedListRenderOptions.MinimalWithItemCountText)
    </div>

Controller :

public ActionResult Index(string search = null, int page = 1)
        {
            ViewBag.search = search;
            var model = _db.Employees
                .Where(r => search == null || r.Name.StartsWith(search) || r.Name.Contains(search))
                .Select(r => new EmployeeViewModel
                {
                    Id = r.Id,
                    Name = r.Name,
                    City = r.City,
                    Country = r.Country,
                }).ToPagedList(page, 10);
            return View(model);
        }