生成字符串旋转的 Pythonic 方式

Question

考虑一个字符串 '1234'。您需要一个生成所有旋转的函数:'1234'、'3412'、'4123'、'2341'。我创建了一个简单的测试套件:

assert rotations('123') == set(['123', '231', '312'])
assert rotations('111') == set(['111'])
assert rotations('197') == set(['197', '971', '719'])

执行此操作的 pythonic 方法是什么？我完成了下面的代码

def rotations(num):
    str_num = str(num)
    result = set()
    for mid in xrange(len(str_num)):
        result.add(
            str_num[mid:] + str_num[:mid]
        )
    return result

Answer 1

s='1234'
z = {s[x:]+s[:x] for x in range(len(s))}