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python - SQLAlchemy 连接来自同一个表的多个列

转载 作者:太空狗 更新时间:2023-10-30 00:43:59 24 4
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class Match(Base):
__tablename__ = 'matches'

id = Column(Integer, primary_key=True)
date = Column(Date, nullable=False)
time = Column(Time, nullable=True)
league_id = Column(ForeignKey('leagues.id'), nullable=False, index=True)
league = relationship('League', backref='matches')
type = Column(enums.matches_types)
home_team_id = Column(ForeignKey('teams.id'), nullable=False, index=True)
home_team = relationship('Team', foreign_keys=[home_team_id], backref='home_matches')
away_team_id = Column(ForeignKey('teams.id'), nullable=False, index=True)


class Team(Base):
__tablename__ = 'teams'

id = Column(Integer, primary_key=True)
name = Column(String, nullable=False)
country_id = Column(ForeignKey('countries.id'), nullable=False, index=True)
country = relationship('Country', backref='teams')

我需要编写一个连接列和团队表的查询,以显示本地团队和客场团队的团队信息。

Session.query(Match.date, Match.home_team.name, Match_away_team.name).joins(Team)

这将返回 Can't determine join between 'matches' and 'teams';表之间有多个外键约束关系。请明确指定此连接的“onclause”

最佳答案

首先,您的代码不起作用的原因是 SQLAlchemy 不知道您是否要加入 Team通过home_teamaway_team ,所以你必须告诉它。此外,您需要加入 Team两次,这使事情更加复杂。

使用 joinedload 可以更轻松地完成此操作:

matches = session.query(Match).options(joinedload(Match.home_team),
joinedload(Match.away_team))
for m in matches:
print m.date, m.home_team, m.away_team

m.home_teamm.away_team将在与 m 相同的查询中加载使用 JOIN .

如果您坚持使用明确的 .join()你必须 alias Team实体(未测试):

home = aliased(Team)
away = aliased(Team)
q = session.query(Match.date, home, away).join(home, Match.home_team) \
.join(away, Match.away_team)
for date, home_team, away_team in q:
print date, home_team, away_team

关于python - SQLAlchemy 连接来自同一个表的多个列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35327701/

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