python - 不能在 pygame.draw.circle 中使用变量？

Question

当我尝试使用变量制作形状时，我不断收到此错误消息:

“TypeError:需要整数参数，得到了 float ”

import pygame._view
import pygame, sys
from pygame.locals import *
import random

pygame.init()

...

barrel = pygame.image.load("images\Barrel.gif")
barrel_create = 0
barrelx = screen.get_height()- barrel.get_height()
barrely = screen.get_width()/2 - barrel.get_width()/2
barrel_exist = 0
explosion_delay = 0

...

while running:

    if barrel_exist == 0:
        if barrel_create == 500:
            barrely = 200
        barrelx = random.randint(0,400)
        barrel_exist = 1
    if barrel_exist == 1:
        barrely = barrely + 0.1
        if barrely > 400:
            barrel_exist = 0

    if explosion_delay > 0:
        pygame.draw.circle(screen, (0,255,0), (barrelx, barrely), 64, 0)
    explosion_delay = explosion_delay + 1

    if explosion_delay == 100:
    explosion_delay = 0

当枪管被“射击”时，explosion_delay > 0。

Answer 1

barrely = barrely + 0.1

barrely 由于这一行，在某些时候必须是一个 float 。

我认为您应该执行 pygame.draw.circle(screen, (0,255,0), (int(barrelx), int(barrely)), 64, 0) 将变量截断为函数需要的整数。