python - 我如何在 Django 中对类 View 进行身份验证

Question

在 Django 文档中，他们这样说 https://docs.djangoproject.com/en/dev/topics/auth/default/#user-objects

from django.contrib.auth.decorators import login_required

@login_required(login_url='/accounts/login/')
def my_view(request):

但是我如何在基于类的 View 上使用 login_required

@login_required
classMyCreateView(CreateView):

这给出了错误

'function' 对象没有属性 'as_view'

Answer 1

你可以通过多种方式做到这一点，比如

https://docs.djangoproject.com/en/dev/topics/class-based-views/#decorating-class-based-views

1. 要么是这个

 urlpatterns = patterns('',
        (r'^about/', login_required(TemplateView.as_view(template_name="secret.html"))),
        (r'^vote/', permission_required('polls.can_vote')(VoteView.as_view())),
    )

1. 或者这个

class ProtectedView(TemplateView):
    template_name = 'secret.html'

    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(ProtectedView, self).dispatch(*args, **kwargs)