ios - 使用 nsmutabledictionary 创建嵌套的 JSON 字符串

Question

我正在尝试创建以下格式的 json 字符串:

{
  "cat_id" : 4992, 
  "brand"  : "Toshiba",
  "weight" : { "gte":1000000, "lt":1500000 },
  "sitedetails" : {
      "name" : "newegg.com",
      "latestoffers" : {
          "currency": "USD",
          "price"   : { "gte" : 100 } 
     }
 }
}

我用下面的方法生成这个:

-(void)queryBuilderWithObj:(NSString *)object andKeyValue:(NSString *)key{
NSLog(@"object %@ and key %@",object,key);


if([key rangeOfString:@","].location == NSNotFound){
    [querybuild setObject:object forKey:key];
}else{
    NSArray *tempArray = [key componentsSeparatedByString:@","];
    int index = tempArray.count - 1;
    NSMutableDictionary *tempDict = [[NSMutableDictionary alloc] init];
    while (index) {
        if (index == tempArray.count - 1) {
            if([querybuild objectForKey:[tempArray objectAtIndex:index]]){
                NSMutableArray *objArray = [[NSMutableArray alloc] init];
                [objArray addObject:[querybuild objectForKey:[tempArray objectAtIndex:index]]];
                [objArray addObject:object];
                [tempDict setObject:objArray forKey:[tempArray objectAtIndex:index]];


            }else{
                [tempDict setObject:object forKey:[tempArray objectAtIndex:index]];
            }

        }else{
            if([querybuild objectForKey:[tempArray objectAtIndex:index]]){

                NSMutableArray *objArray = [[NSMutableArray alloc] init];
                [objArray addObject:[querybuild objectForKey:[tempArray objectAtIndex:index]]];

                NSMutableDictionary *subDict = [[NSMutableDictionary alloc] init];
                [subDict setDictionary:tempDict];

                [objArray addObject:subDict];
                [tempDict setObject:objArray forKey:[tempArray objectAtIndex:index]];



            }else{
                NSMutableDictionary *subDict = [[NSMutableDictionary alloc] init];
                [subDict setDictionary:tempDict];
                [tempDict setObject:subDict forKey:[tempArray objectAtIndex:index]];
            }
        }
        index --;
    }



    [querybuild setObject:tempDict forKey:[tempArray objectAtIndex:0]];

}
NSLog(@"querybuild %@ ",querybuild);


}

最终生成的nsmutabledictionary是:

 querybuild {
brand = Toshiba;
"cat_id" = 4992;
sitedetails =     {
    gte = 100;
    latestoffers =         {
        gte = 100;
        price =             {
            gte = 100;
        };
    };
    price =         {
        gte = 100;
    };
};
weight =     {
    lt = 1500000;
};

}

我按如下方式传递了对象和 key :

[sem queryBuilderWithObj:@"4992" andKeyValue:@"cat_id" ];
[sem queryBuilderWithObj:@"Toshiba" andKeyValue:@"brand"];
[sem queryBuilderWithObj:@"1000000" andKeyValue:@"weight,gte"];
[sem queryBuilderWithObj:@"1500000" andKeyValue:@"weight,lt"];
[sem queryBuilderWithObj:@"newegg.com"andKeyValue:@"sitedetails,name" ];
[sem queryBuilderWithObj:@"USD" andKeyValue:@"sitedetails,latestoffers,currency"];
[sem queryBuilderWithObj:@"100" andKeyValue:@"sitedetails,latestoffers,price,gte"];

关于如何生成所需输出的任何想法？ querybuild是把这个方法中的nsmutabledictionary对象声明为类变量吗？

Answer 1

如果你想要这个最好的方法是创建更多的字典示例:

NSMutableDictionary *json= [[NSMutableDictionary alloc] init];
[json setObject:@"4992" forKey:@"cat_id"];
[json setObject:@"Toshiba" forKey:@"brand"];
//create weight object
NSMutableDictionary *weight= [[NSMutableDictionary alloc] init];
[weight setObject:@"1000000" forKey:@"gte"];
[weight setObject:@"1500000" forKey:@"lt"];
//attach the object
[json setObject:weight forKey:@"weight"];
//create sitedetails objects
NSMutableDictionary *sitedetails= [[NSMutableDictionary alloc] init];
[sitedetails setObject:@"newegg.com" forKey:@"name"];
//create latestoffers objects
NSMutableDictionary *latestoffers= [[NSMutableDictionary alloc] init];
[latestoffers setObject:@"USD" forKey:@"currency"];
//new dictionary for price
[sitedetails setObject:latestoffers forKey:@"latestoffers"];
[json setObject:sitedetails forKey:@"sitedetails"];
NSLog(@"%@",json);

在你可以将字典转换成json字符串后...

-(NSString*)getJsonStringByDictionary:(NSDictionary*)dictionary{
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:dictionary
                                                   options:NSJSONWritingPrettyPrinted
                                                     error:&error];
return [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
}