ios - 圈复杂度违规 : Function should have complexity 10 or less: currently complexity equals 13 (cyclomatic_complexity)

Question

我在 swift3 中有以下代码，我正在使用 swift lint 对代码进行 linting。给出代码如下:

    func selectedMenuInLoggedOutState(sender: UIButton) {
    switch sender.tag {
    case 1:
      if let menu = LeftGuestMenu(rawValue: 0) {
        self.changeGuestViewController(menu)
      }
    case 2:
      if let menu = LeftGuestMenu(rawValue: 1) {
        self.changeGuestViewController(menu)
      }
    case 3:
      if let menu = LeftGuestMenu(rawValue: 2) {
        self.changeGuestViewController(menu)
      }
    case 4:
      if let menu = LeftGuestMenu(rawValue: 3) {
        self.changeGuestViewController(menu)
      }
    case 5:
      if let menu = LeftGuestMenu(rawValue: 4) {
        self.changeGuestViewController(menu)
      }
    case 6:
      if let menu = LeftGuestMenu(rawValue: 5) {
        self.changeGuestViewController(menu)
      }
    default:
      break
    }
  }

swift lint 生成“违反圈复杂度”警告。为什么会出现此警告？如何解决？

Answer 1

该方法太复杂。但不是重写代码，您可以从 cyclomatic_complexity 计算中排除 switches (因为它们完全可读)，如下所示:

cyclomatic_complexity:
  ignores_case_statements: true