objective-c - 将小数坐标转换成度、分、秒、方向

Question

到目前为止，我有以下内容，但无法想出一个简洁的方法来在没有一堆困惑的 if 语句的情况下输入方向字母。有任何想法吗？理想情况下，我想用一个类别扩展 CLLocation 类来执行此操作。

-(NSString *)nicePosition{

double latitude = [self.latitude doubleValue];
double longitude = [self.longitude doubleValue];

int latSeconds = (int)round(latitude * 3600);
int latDegrees = latSeconds / 3600;
latSeconds = abs(latSeconds % 3600);
int latMinutes = latSeconds / 60;
latSeconds %= 60;

int longSeconds = (int)round(longitude * 3600);
int longDegrees = longSeconds / 3600;
longSeconds = abs(longSeconds % 3600);
int longMinutes = longSeconds / 60;
longSeconds %= 60;

//TODO: Use N,E,S,W notation in lat/long

return [NSString stringWithFormat:@"%i° %i' %i\", %i° %i' %i\"", latDegrees, latMinutes, latSeconds, longDegrees, longMinutes, longSeconds];
}

为了记录，我做了以下事情。

-(NSString *)nicePosition{

double latitude = [self.latitude doubleValue];
double longitude = [self.longitude doubleValue];

int latSeconds = (int)round(abs(latitude * 3600));
int latDegrees = latSeconds / 3600;
latSeconds = latSeconds % 3600;
int latMinutes = latSeconds / 60;
latSeconds %= 60;

int longSeconds = (int)round(abs(longitude * 3600));
int longDegrees = longSeconds / 3600;
longSeconds = longSeconds % 3600;
int longMinutes = longSeconds / 60;
longSeconds %= 60;

char latDirection = (latitude >= 0) ? 'N' : 'S';
char longDirection = (longitude >= 0) ? 'E' : 'W';

return [NSString stringWithFormat:@"%i° %i' %i\" %c, %i° %i' %i\" %c", latDegrees, latMinutes, latSeconds, latDirection, longDegrees, longMinutes, longSeconds, longDirection];
}

Answer 1

标准方式:

char lonLetter = (lon > 0) ? 'E' : 'W';
char latLetter = (lat > 0) ? 'N' : 'S';