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我有一个 json 对象:
@interface Order : NSObject
@property (nonatomic, retain) NSString *OrderId;
@property (nonatomic, retain) NSString *Title;
@property (nonatomic, retain) NSString *Weight;
- (NSMutableDictionary *)toNSDictionary;
...
- (NSMutableDictionary *)toNSDictionary
{
NSMutableDictionary *dictionary = [[NSMutableDictionary alloc] init];
[dictionary setValue:self.OrderId forKey:@"OrderId"];
[dictionary setValue:self.Title forKey:@"Title"];
[dictionary setValue:self.Weight forKey:@"Weight"];
return dictionary;
}
在字符串中是:
{
"Title" : "test",
"Weight" : "32",
"OrderId" : "55"
}
我得到带有代码的字符串 JSON:
NSMutableDictionary* str = [o toNSDictionary];
NSError *writeError = nil;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:str options:NSJSONWritingPrettyPrinted error:&writeError];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
现在我需要从 JSON 字符串创建和映射对象:
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSError *e;
NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:jsonData options:nil error:&e];
这会返回我填充的 NSDictionary。我应该怎么做才能从这个字典中获取对象?
最佳答案
向 Order
添加一个新的 initWithDictionary:
方法:
- (instancetype)initWithDictionary:(NSDictionary*)dictionary {
if (self = [super init]) {
self.OrderId = dictionary[@"OrderId"];
self.Title = dictionary[@"Title"];
self.Weight = dictionary[@"Weight"];
}
return self;
}
不要忘记将initWithDictionary
的签名添加到Order.h
文件
在获取JSON的方法中:
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSError *e;
NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:jsonData options:nil error:&e];
Order *order = [[Order alloc] initWithDictionary:dict];
关于ios - 如何将 NSDictionary 转换为自定义对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21329793/
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