ios - 如何将 CBUUID 转换为字符串

Question

我找不到任何官方方法从 CBUUID 中取回 UUID 字符串。这些 UUID 的长度可以是 2 或 16 个字节。

目标是将 CBUUID 作为字符串存储在某个文件中，然后使用 [CBUUID UUIDWithString:] 等复活。这是我目前所拥有的。

// returns a simple 4 byte string for 16bit uuids, 128 bit uuids are in standard 8-4-4-4-12 format
// the resulting string can be passed into [CBUUID UUIDWithString:]
+(NSString*)CBUUIDToString:(CBUUID*)cbuuid;
{
    NSData* data = cbuuid.data;
    if ([data length] == 2)
    {
        const unsigned char *tokenBytes = [data bytes];
        return [NSString stringWithFormat:@"%02x%02x", tokenBytes[0], tokenBytes[1]];
    }
    else if ([data length] == 16)
    {
        NSUUID* nsuuid = [[NSUUID alloc] initWithUUIDBytes:[data bytes]];
        return [nsuuid UUIDString];
    }

    return [cbuuid description]; // an error?
}

Answer 1

我装配了以下类别来为 CBUUID 执行此操作:

@interface CBUUID (StringExtraction)

- (NSString *)representativeString;

@end

@implementation CBUUID (StringExtraction)

- (NSString *)representativeString;
{
    NSData *data = [self data];

    NSUInteger bytesToConvert = [data length];
    const unsigned char *uuidBytes = [data bytes];
    NSMutableString *outputString = [NSMutableString stringWithCapacity:16];

    for (NSUInteger currentByteIndex = 0; currentByteIndex < bytesToConvert; currentByteIndex++)
    {
        switch (currentByteIndex)
        {
            case 3:
            case 5:
            case 7:
            case 9:[outputString appendFormat:@"%02x-", uuidBytes[currentByteIndex]]; break;
            default:[outputString appendFormat:@"%02x", uuidBytes[currentByteIndex]];
        }

    }

    return outputString;
}

@end

对于这个输入:

NSLog(@"UUID string: %@", [[CBUUID UUIDWithString:@"0bd51666-e7cb-469b-8e4d-2742f1ba77cc"] representativeString]);
NSLog(@"UUID string2: %@", [[CBUUID UUIDWithString:@"1800"] representativeString]);

它产生以下输出:

UUID string: 0bd51666-e7cb-469b-8e4d-2742f1ba77cc
UUID string2: 1800

并为 16 字节 UUID 保留适当的连字符，同时支持简单的 2 字节 UUID。