CSS 3 形状 : "Inverse Circle" or "Cut Out Circle"

Question

我想创建一个形状，我将其描述为“反圆”:

图片有点不准确，因为黑线应该沿着 div 元素的外边界继续。

这是我目前拥有的演示:http://jsfiddle.net/n9fTF/

没有图像的 CSS 甚至可能吗？

Answer 1

更新:CSS3 径向背景渐变选项

(对于那些支持它的浏览器——在 FF 和 Chrome 中测试——IE10，Safari 应该也可以)。

我的原始答案的一个“问题”是那些没有坚实背景的情况。此更新创建了相同的效果，允许在圆和它的反向切口之间有一个透明的“间隙”。

See example fiddle .

CSS

.inversePair {
    border: 1px solid black;
    display: inline-block;    
    position: relative;    
    height: 100px;
    text-align: center;
    line-height: 100px;
    vertical-align: middle;
}

#a {
    width: 100px;
    border-radius: 50px;
    background: grey;
    z-index: 1;
}

#b {
    width: 200px;
    /* need to play with margin/padding adjustment
       based on your desired "gap" */
    padding-left: 30px;
    margin-left: -30px;
    /* real borders */
    border-left: none;
    -webkit-border-top-right-radius: 20px;
    -webkit-border-bottom-right-radius: 20px;
    -moz-border-radius-topright: 20px;
    -moz-border-radius-bottomright: 20px;
    border-top-right-radius: 20px;
    border-bottom-right-radius: 20px;
    /* the inverse circle "cut" */
    background-image: -moz-radial-gradient(
        -23px 50%, /* the -23px left position varies by your "gap" */
        circle closest-corner, /* keep radius to half height */
        transparent 0, /* transparent at center */
        transparent 55px, /*transparent at edge of gap */
        black 56px, /* start circle "border" */
        grey 57px /* end circle border and begin color of rest of background */
    );
    background-image: -webkit-radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, black 56px, grey 57px);
    background-image: -ms-radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, black 56px, grey 57px);
    background-image: -o-radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, black 56px, grey 57px);
    background-image: radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, black 56px, grey 57px);
}

原始答案

为了让 z-indexing 工作(this seems to ignore the negative z-index)付出了比我预期更多的努力，然而，this gives a nice clean look (在 IE9、FF、Chrome 中测试):

HTML

<div id="a" class="inversePair">A</div>
<div id="b" class="inversePair">B</div>

CSS

.inversePair {
    border: 1px solid black;
    background: grey;
    display: inline-block;    
    position: relative;    
    height: 100px;
    text-align: center;
    line-height: 100px;
    vertical-align: middle;
}

#a {
    width: 100px;
    border-radius: 50px;
}

#a:before {
    content:' ';
    left: -6px;
    top: -6px;
    position: absolute;
    z-index: -1;
    width: 112px; /* 5px gap */
    height: 112px;
    border-radius: 56px;
    background-color: white;
} 

#b {
    width: 200px;
    z-index: -2;
    padding-left: 50px;
    margin-left: -55px;
    overflow: hidden;
    -webkit-border-top-right-radius: 20px;
    -webkit-border-bottom-right-radius: 20px;
    -moz-border-radius-topright: 20px;
    -moz-border-radius-bottomright: 20px;
    border-top-right-radius: 20px;
    border-bottom-right-radius: 20px;
}

#b:before {
    content:' ';
    left: -58px;
    top: -7px;
    position: absolute;
    width: 114px; /* 5px gap, 1px border */
    height: 114px;
    border-radius: 57px;
    background-color: black;
}