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ruby-on-rails - 通过 API 创建资源时 Rails 5 ActiveRecord::SerializationTypeMismatch

转载 作者:数据小太阳 更新时间:2023-10-29 09:00:56 25 4
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我正在为 API 使用 Rails 5 (beta3) 应用程序。我的模型有一个序列化属性,序列化为一个数组。当我从 Postman 发送测试请求时,出现以下错误:

ActiveRecord::SerializationTypeMismatch (Attribute was supposed to be a Array, but was a String. -- "[\"amat\",\"bmat\",\"cmat\"]"):

app/controllers/api/v1/services_controller.rb:23:in `create'
Rendered vendor/cache/gems/actionpack-5.0.0.beta3/lib/action_dispatch/middleware/templates/rescues/_source.html.erb (3.1ms)
Rendered vendor/cache/gems/actionpack-5.0.0.beta3/lib/action_dispatch/middleware/templates/rescues/_trace.html.erb (1.3ms)
Rendered vendor/cache/gems/actionpack-5.0.0.beta3/lib/action_dispatch/middleware/templates/rescues/_request_and_response.html.erb (0.8ms)
Rendered vendor/cache/gems/actionpack-5.0.0.beta3/lib/action_dispatch/middleware/templates/rescues/diagnostics.html.erb within rescues/layout (15.3ms)

我明白错误的含义,但我无法序列化从发布请求中获得的数据。在尝试创建请求之前,我不知道如何或在哪里序列化它。

我的 Controller 的相关部分:

before_action :set_service, only: [:show, :edit, :update, :destroy]

def create
@service = Service.new(service_params)
if @service.save
render json: {message: 'Service created.'}, status: 200
else
render json: {message: 'Error creating Service.'}, status: 500
end
end

private
def set_service
@service = Service.find(params[:id])
end

def service_params
params.require(:service).permit(:name, :sub_service, :material, :parts)
end

服务模式:

class Service < ApplicationRecord
serialize :parts,Array
end

我以原始 JSON 格式发送请求:

{
"service" : {
"name": "Foiling",
"sub_service":"Full",
"material":"plastic",
"parts":["parta","partb","partc"]
}
}

最佳答案

我想通了,我需要明确地告诉 rails 期待参数中的数组:

def service_params
params.require(:service).permit(:name, :sub_service, :material, :parts => [])
end

关于ruby-on-rails - 通过 API 创建资源时 Rails 5 ActiveRecord::SerializationTypeMismatch,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35860462/

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