Ruby:根据条件调用方法

Question

我有以下代码:

class Engine
  attr_accessor :isRunning

  def initialize
    @isRunning = false
    @commands = ["left", "right", "brake", "accelerate", "quit"]
  end

  def start
    self.isRunning = true;
    while(self.isRunning)
      command = gets.chomp!

      if(@commands.include? command)
        puts "OK."
      else
        puts "> #{command} Unknown Command."
      end

      if(command=="quit") then
        self.stop
        puts "Quitting!"
      end
    end

  end

  def stop
    self.isRunning = false;
  end

end

如您所见，它非常简单，但是，我正在尝试弄清楚如何根据条件调用方法。如果我像这样在 Engine 类中实现一堆方法，比如 methodOne 和 methodTwo:

@commands = ["left", "right", "brake", "accelerate", "quit", "methodOne", "methodTwo"]

def methodOne

end

def methodTwo

end

def parseCommand(command)
   if(command=="methodOne") then
   self.methodOne
   end
   if(command=="methodTwo") then
   self.methodTwo
   end
end

我可以简单地调用这些方法吗？现在，我不得不写一大堆 if 语句，如果可以更优雅地完成，我宁愿省略它的 future 维护。

Answer 1

使用 self.send("methodname")

您可以在 Docs 中阅读更多相关信息

您的代码可能如下所示:

class Engine
  # ...code ...
  def parseCommands(commands)
    commands.each{|c_command| self.send(c_command) }
  end 
  # ...code ...
end

@commands = ["left", "right", "brake", "accelerate", "quit", "methodOne", "methodTwo"]
engineInstance.parseCommands(@commands)