gpt4 book ai didi

ruby - 如何在 ruby​​ 中进行 base58 编码?

转载 作者:数据小太阳 更新时间:2023-10-29 08:48:15 25 4
gpt4 key购买 nike

我正在尝试按照 Protoshares wiki 中的说明将原始格式的 Bitcoin 钱包地址编码为 Base58 格式。

Protoshares 地址以 P ( version number 56 ) 开头。

我已经给出了交易的原始地址。看起来像这样:

028401a2e512b1b91b882ee1c9291cd407c10916bf791662f7189c9c805643e51c

现在我已经按照 wiki 中的指南一步步进行操作,我的 ruby​​ 代码如下所示:

# 1 - Take the corresponding public key generated with it (65 bytes, 1 byte 0x04, 32 bytes corresponding to X coordinate, 32 bytes corresponding to Y coordinate)
sender = '028401a2e512b1b91b882ee1c9291cd407c10916bf791662f7189c9c805643e51c'
# 2 - Perform SHA-256 hashing on the public key
sender = Digest::SHA256.new.update(sender)
# 3 - Perform RIPEMD-160 hashing on the result of SHA-256
sender = Digest::RMD160.new.update(sender.to_s)
# 4 - Add version byte in front of RIPEMD-160 hash (0x00 for Main Network)
sender = '00' + sender.to_s
# 5 - Perform SHA-256 hash on the extended RIPEMD-160 result
checksum = Digest::SHA256.new.update(sender.to_s)
# 6 - Perform SHA-256 hash on the result of the previous SHA-256 hash
checksum = Digest::SHA256.new.update(checksum.to_s)
# 7 - Take the first 4 bytes of the second SHA-256 hash. This is the address checksum
checksum = checksum.to_s[0,8]
# 8 - Add the 4 checksum bytes from point 7 at the end of extended RIPEMD-160 hash from point 4. This is the 25-byte binary Bitcoin Address.
sender += checksum

到目前为止,这似乎运作良好。我目前的结果是这样的:

0073eb40b21b02c08e93f6ef1bec5828763ac89e456c2f6fec

但现在我卡住了。我正在使用 base58 gem by dougal 并尝试最终对地址进行编码:

# 9 - Convert the result from a byte string into a base58 string using Base58Check encoding. This is the most commonly used Bitcoin Address format 
sender = Base58.encode(sender)

但我遇到以下问题:

/path/to/base58.rb:23:in `int_to_base58': Value passed is not an Integer. (ArgumentError)

当然不是整数。我在这里搞砸了数据类型吗?如何才能使其正常工作?

谢谢!

最佳答案

对我来说,这看起来像是一个字符串中的十六进制数,将其设为一个数字:

2.0.0p247 :001 > require 'base58'
=> true
2.0.0p247 :002 > x = '0073eb40b21b02c08e93f6ef1bec5828763ac89e456c2f6fec'
=> "0073eb40b21b02c08e93f6ef1bec5828763ac89e456c2f6fec"
2.0.0p247 :003 > Base58.encode(x.to_i(16))
=> "byVwGWzMZZ7HwsufSQx6T2pRapGZWdkAL"

不确定您的预期输出是什么,但这会执行...

关于ruby - 如何在 ruby​​ 中进行 base58 编码?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20860641/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com