ruby-on-rails - Ruby 如何迭代一个集合并在不存在的情况下创建一个散列键，或者如果键存在则添加到该值

Question

这是我发现自己经常使用的模式，我想知道内置库中是否有某些东西可以在不添加所有这些控制流语句的情况下执行此操作。我有的是:

input = <<TEXT
/us/programming/sports:model.channel.tnt.name
/us/programming/sports:model.channel.spice.name
/us/programming/sports:model.classificationwebgenre.us-entertainment.programming_link_text
/international-sports/package:model.language.international-sports.name
/brazilian/programming/sports:model.package.hbo-extra.description
TEXT


def self.create_hash(text)
  output = {}
  text.each_line("\n") do |line|
    split_lines = line.split(":")
    if output.has_key?(split_lines.first)
      output[split_lines.first] << split_lines[1][0..-2]
    else
      output[split_lines.first] = [split_lines[1][0..-2]]
    end
  end
  output
end

结束

这个的输出也是:

{
      "/us/programming/sports" => ["model.channel.tnt.name", "model.channel.spice.name", "model.classificationwebgenre.us-entertainment.programming_link_text"],
      "/international-sports/package" => ["model.language.international-sports.name"],
      "/brazilian/programming/sports" => ["model.package.hbo-extra.description"]
    }

我写这篇文章的方式是否只是让事情变得过于复杂？有没有一种惯用的方法可以用 ruby 写这个？提前致谢。

Answer 1

不确定是否更快，但更干净

def self.create_hash(text)
  output = {}
  text.each_line("\n") do |line|
    split_lines = line.split(":")
    output[split_lines.first] ||= []
    output[split_lines.first] << split_lines[1][0..-2]
  end
  output
end