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ruby - 如何在 ruby​​ 中混合必需参数和可选参数?

转载 作者:数据小太阳 更新时间:2023-10-29 08:38:43 26 4
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我正在研究 ruby​​,以下是我的代码片段。我尝试混合必需的参数和选项参数。但它给了我一个错误:

def my_method(a, b, *p, d)
puts a
puts b
puts "content of p is :" + p.to_s
puts d
end

my_method(10, 20, 34, 45)

错误片段:

syntax error def my_method(a, b, *p, d)
^

这个错误的原因是什么?

注意:我使用的是“ruby 1.8.5” ruby 版本

最佳答案

您的代码在任何最新版本的 Ruby 中都可以正常工作。但是,它在 非常旧 的 Ruby 版本中不起作用,因为仅在 Ruby 1.9.0 中引入了在 splat 参数之后需要的位置参数。

Ruby 中参数列表的伪正则表达式是这样的:

mand* opt* splat? mand* (mand_kw | opt_kw)* kwsplat? block?

这是一个例子:

def foo(m1, m2, o1=:o1, o2=:o2, *splat, m3, m4, 
ok1: :ok1, mk1:, mk2:, ok2: :ok2, **ksplat, &blk)
Hash[local_variables.map {|var| [var, eval(var.to_s)] }]
end

method(:foo).arity
# => -5

method(:foo).parameters
# => [[:req, :m1], [:req, :m2], [:opt, :o1], [:opt, :o2], [:rest, :splat],
# [:req, :m3], [:req, :m4], [:keyreq, :mk1], [:keyreq, :mk2],
# [:key, :ok1], [:key, :ok2], [:keyrest, :ksplat], [:block, :blk]]

foo(1, 2, 3, 4)
# ArgumentError: missing keywords: mk1, mk2

foo(1, 2, 3, mk1: 4, mk2: 5)
# ArgumentError: wrong number of arguments (3 for 4+)

foo(1, 2, 3, 4, mk1: 5, mk2: 6)
# => { m1: 1, m2: 2, o1: :o1, o2: :o2, splat: [], m3: 3, m4: 4,
# ok1: :ok1, mk1: 5, mk2: 6, ok2: :ok2, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, mk1: 6, mk2: 7)
# => { m1: 1, m2: 2, o1: 3, o2: :o2, splat: [], m3: 4, m4: 5,
# ok1: :ok1, mk1: 6, mk2: 7, ok2: :ok2, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, mk1: 7, mk2: 8)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [], m3: 5, m4: 6,
# ok1: :ok1, mk1: 7, mk2: 8, ok2: :ok2, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, mk1: 8, mk2: 9)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5], m3: 6, m4: 7,
# ok1: :ok1, mk1: 8, mk2: 9, ok2: :ok2, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, 8, mk1: 9, mk2: 10)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5, 6], m3: 7, m4: 8,
# ok1: :ok1, mk1: 9, mk2: 10, ok2: :ok2, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, 8, ok1: 9, mk1: 10, mk2: 11)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5, 6], m3: 7, m4: 8,
# ok1: 9, mk1: 10, mk2: 11, ok2: :ok2, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, 8, ok1: 9, mk1: 10, mk2: 11, ok2: 12)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5, 6], m3: 7, m4: 8,
# ok1: 9, mk1: 10, mk2: 11, ok2: 12, ksplat: {},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, 8, ok1: 9, mk1: 10, mk2: 11, ok2: 12, k3: 13)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5, 6], m3: 7, m4: 8,
# ok1: 9, mk1: 10, mk2: 11, ok2: 12, ksplat: {k3: 13},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, 8, ok1: 9, mk1: 10, mk2: 11, ok2: 12, k3: 13, k4: 14)
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5, 6], m3: 7, m4: 8,
# ok1: 9, mk1: 10, mk2: 11, ok2: 12, ksplat: {k3: 13, k4: 14},
# blk: nil }

foo(1, 2, 3, 4, 5, 6, 7, 8,
ok1: 9, ok2: 10, mk1: 11, mk2: 12, k3: 13, k4: 14) do 15 end
# => { m1: 1, m2: 2, o1: 3, o2: 4, splat: [5, 6], m3: 7, m4: 8,
# ok1: 9, mk1: 10, mk2: 11, ok2: 12, ksplat: {k3: 13, k4: 14},
# blk: #<Proc:0xdeadbeefc00l42@(irb):15> }

关于ruby - 如何在 ruby​​ 中混合必需参数和可选参数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18331107/

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