"pig latin"的 Ruby 映射函数

Question

我正在尝试编写一个 ruby​​ 函数，该函数接收一串单词并将其转换为 Pig Latin 。我将字符串分解成一个数组，并尝试遍历每个元素。当输入“eat pie”时，结果是“eat ie”，但我不确定为什么。

string = "eat pie"    
array = string.split(" ")

array.map do |word| 

 if word[0].chr == "a" || word[0].chr == "e" || word[0].chr == "i" || word[0].chr == "o" || word[0].chr == "u"

   word = word + "ay"

 elsif word[1].chr == "a" || word[1].chr == "i" || word[1].chr == "o" || word[1].chr == "u"
  temp = word[0]
  word[0] = ""
  word = word + temp
  word = word + "ay"

elsif word[2].chr == "a" || word[2].chr == "i" || word[2].chr == "o" || word[2].chr == "u"
  temp = word[0] + word[1]
  word[0] = ""
  word[0] = ""
  word = word + temp 
  word = word + "ay"

else ## three consonants
  temp = word[0] + word[1] + word[2]
  word[0] = ""
  word[0] = ""
  word[0] = ""
  word = word + temp 
  word = word + "ay"

 end ## end of if statement

end ## end of iteration 

puts array.join(" ")

Answer 1

同意提供的其他答案，这里是您的代码的一个稍微不那么冗长的版本，以防它对您有所帮助。

input = 'pig latin is awesome'

arr = input.split(' ').map do |wrd|
    if %w(a e i o u).include? wrd[0]
      wrd + 'ay'
    elsif %w(a i o u).include? wrd[1]
      wrd[1..-1] + wrd[0] + 'ay'
    elsif %w(a i o u).include? wrd[2]
      wrd[2..-1] + wrd[0] + wrd[1] + 'ay'
    else
      wrd[3..-1] + wrd[0] + wrd[1] + wrd[2] + 'ay'
    end
end.join(' ')

puts arr