ruby-on-rails - Rails 路由变量

Question

订单可以有多种状态。我想为那些创建命名路由。我需要将状态作为参数传递给 Controller ​​。这是我的想法，但显然行不通。

match "order/:state/:id" => "orders#%{state}", as: "%{state}"

所以我希望 order/address/17 路由到 orders#address，其中 :state 和 :id 作为参数传入。同样，order/shipping/17 会路由到 orders#shipping，同样会传入 :state 和 :id。

这是 Controller 。

class OrdersController < ApplicationController

  before_filter :load_order, only: [:address, :shipping, :confirmation, :receipt]
  before_filter :validate_state, only: [:address, :shipping, :confirmation, :receipt]


  def address
    @order.build_billing_address unless @order.billing_address
    @order.build_shipping_address unless @order.shipping_address
  end


  def shipping
    @shipping_rates = @order.calculate_shipping_rates
  end


  def confirmation

  end


  def receipt

  end

  private 

  def load_order
    @order = Order.find(params[:id])
  end

  # Check to see if the user is on the correct action
  def validate_state
    if params[:state]
      unless params[:state] == @order.state
        redirect_to eval("#{@order.state}_path(:#{@order.state},#{@order.id})")
        return
      end
    end
  end

end

这是我们最终的结果:

routes.rb

%w(address shipping confirmation receipt).each do |state|
    match "order/#{state}/:id", :to => "orders##{state}", :as => state, :state => state
end

orders_controller.rb

def validate_state
    if params[:state]
      unless params[:state] == @order.state
        redirect_to(eval("#{@order.state}_path(@order)"))
        return
      end
    end
  end

Answer 1

您将无法使用那种语法创建动态命名路由，但您基本上只是使用 :state 作为 :action。如果将 :state 替换为 :action 并手动指定 Controller ，它将起作用。显然，您必须更改代码以查看 params[:action] 而不是 params[:state](或将该变量映射到 before_filter 中)，但除此之外它应该可以正常工作。

match "order/:action/:id", :controller => "orders"

请注意，如果订单具有 RESTful 资源映射，如 create 或 delete，此路由将允许对它们发出 GET 请求，这很糟糕；您可能只想为要完成的每个操作添加显式路由。这将让您获得 params[:state]，以及:

%w(address shipping).each do |state|
  match "order/#{state}/:id", :to => "orders##{state}", :as => state, :state => state
end