ruby - 通过键数组设置 ruby​​ 哈希元素值

Question

这是我得到的:

hash = {:a => {:b => [{:c => old_val}]}}
keys = [:a, :b, 0, :c]
new_val = 10

散列结构和 key 集可以变化。
我需要得到

hash[:a][:b][0][:c] == new_val

谢谢!

Answer 1

您可以使用 inject遍历你的嵌套结构:

hash = {:a => {:b => [{:c => "foo"}]}}
keys = [:a, :b, 0, :c]

keys.inject(hash) {|structure, key| structure[key]}
# => "foo"

因此，您只需要修改它以对最后一个键进行设置。也许像

last_key = keys.pop
# => :c

nested_hash = keys.inject(hash) {|structure, key| structure[key]}
# => {:c => "foo"}

nested_hash[last_key] = "bar"

hash
# => {:a => {:b => [{:c => "bar"}]}}