ruby - 将单词与前一个字符切片

Question

有没有更好的方法在 ruby​​ 中分割单词？我的解决方案:

str="TAMILNADU"
pairs=[]
numPairs= str.length-1
i=0
while i<numPairs do 
  pairs[i] = str.slice(i,2)
  i+=1
end

结果

["TA", "AM", "MI", "IL", "LN", "NA", "AD", "DU"] 

Answer 1

是的，有:

irb(main):001:0> "TAMILNADU".chars.each_cons(2).map(&:join)
=> ["TA", "AM", "MI", "IL", "LN", "NA", "AD", "DU"]

参见 the documentation of Enumerable#each_cons .