ruby - 超时::循环中的错误异常

Question

我在循环中有这段 ruby​​ 代码:

pid = Process.spawn("my_process_command")
begin
    Timeout.timeout(16) do
        `my_timeout_command`
        Process.wait(pid)
    end
rescue
    system("clear")
    puts 'Process not finished in time, killing it'
    Process.kill('TERM', pid)
end

问题是一旦 Timeout::Error 异常被捕获， block 将被跳过并且循环几乎什么都不做。我该如何解决这个问题？

Answer 1

自Timeout::Error is not a standard error以来，您需要专门针对Timeout:Errorrescue :

pid = Process.spawn("my_process_command")
begin
    Timeout.timeout(16) do
        `my_timeout_command`
        Process.wait(pid)
    end
rescue Timeout::Error
    system("clear")
    puts 'Process not finished in time, killing it'
    Process.kill('TERM', pid)
end