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ruby-on-rails - Rails 不使用模型指定的表

转载 作者:数据小太阳 更新时间:2023-10-29 08:08:17 25 4
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我有一个子类化另一个模型的模型,这个特定模型不使用我指定的表,而是默认返回到试图找到该表的父类。

父类在gem中,子类在 namespace 隔离的引擎中。

父级(在 gem 中):

require_relative 'concerns/user_concerns'
require 'bcrypt'

module CoreModels
module Models
class User < ActiveRecord::Base
self.abstract_class = true

extend FriendlyId
friendly_id :first_name, use: [:slugged, :finders, :history]

before_save :encrypt_password

has_many :group_memberships, :dependent => :delete_all
has_many :groups, :through => :group_memberships, :dependent => :delete_all
has_many :roles, :through => :group_memberships, :dependent => :delete_all

has_many :api_keys

validates :first_name, presence: true
validates :user_name, uniqueness: true, presence: true, length: {minimum: 5}
validates :email, presence: true, confirmation: true, uniqueness: true
validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\z/i
validates :password, presence: true, confirmation: true, length: { minimum: 10 }, if: :new_record?

include CoreModels::Models::Concerns::UserConcerns

before_create{ generate_token(:auth_token) }

def self.authenticate_user(user_name, password)
user = Xaaron::User.find_by_user_name(user_name)
if(user && (user.password == BCrypt::Engine.hash_secret(password, user.salt)))
user
else
nil
end
end

def encrypt_password
if password.present?
self.salt = BCrypt::Engine.generate_salt
self.password = BCrypt::Engine.hash_secret(password, salt)
end
end

def send_password_reset
generate_token(:password_reset_token)
self.password_reset_timestamp = Time.zone.now
save!
UserMailer.password_reset(self).deliver
end

protected
def generate_token(column)
begin
self[column] = SecureRandom.urlsafe_base64
end while User.exists?(column => self[column])
end
end
end
end

child (在引擎中):

require 'core_models/models/user'

module Xaaron
class User < CoreModels::Models::User
self.table_name = 'xaaron_users'
end
end

当我运行我的测试时,其中 135 个失败,一遍又一遍地给我同样的错误:

Failure/Error: setup_group_role_permissions_relations_for_administrator
ActiveRecord::StatementInvalid:
PG::UndefinedTable: ERROR: relation "users" does not exist
LINE 5: WHERE a.attrelid = '"users"'::regclass
^
: SELECT a.attname, format_type(a.atttypid, a.atttypmod),
pg_get_expr(d.adbin, d.adrelid), a.attnotnull, a.atttypid, a.atttypmod
FROM pg_attribute a LEFT JOIN pg_attrdef d
ON a.attrelid = d.adrelid AND a.attnum = d.adnum
WHERE a.attrelid = '"users"'::regclass
AND a.attnum > 0 AND NOT a.attisdropped
ORDER BY a.attnum

这个特殊的方法是:

def setup_group_role_permissions_relations_for_administrator
@user = FactoryGirl.create(:user)
@role = FactoryGirl.create(:admin_role)
@group = FactoryGirl.create(:administrator_group)
@permission = FactoryGirl.create(:can_read)

@role.add_permission = @permission.permission_name
@group.add_role = @role.role_name

@user.add_group_membership(@group, @role)
end

所以你可以看到当我说使用表 x 时它没有听我说。相反,它试图使用一个不存在的表。/我所有的引擎表都是用 xaaron_

命名空间的

更新

经过一些调查,核心问题是 FactoryGirl,如果我们看一下发生在以下位置的第一件事:setup_group_role_permissions_relations_for_administrator 我在做 @user = FactoryGirl.create(:user),当我用 pry 弄清楚那里发生了什么时 - 这就是问题所在,所以让我们看看这个工厂:

FactoryGirl.define do
sequence :user_email do |n|
"user#{n}@example.com"
end

# Allows for multiple user names
sequence :user_name do |n|
"user#{n}"
end

sequence :permission_name do |n|
"can_read#{n}"
end

sequence :role_name do |n|
"Member#{n}"
end


factory :user, :class => Xaaron::User do
first_name 'Adam'
last_name 'Something'
user_name {generate :user_name}
email {generate :user_email}
password 'somePasswordThat_Is$ecure10!'
end

factory :admin, :class => Xaaron::User do
first_name "Sample Admin"
email "a@gmail.com"
user_name "Admin_User_Name"
password "admin_Password10985"
end
end

factory girl 创建用户的方式有问题,因为我可以启动 Rails 控制台并执行 Xaaron::User.all 并且它知道查看 xaaron_users 而不是 users

所以 self.table_name="" 可以工作,但由于某种原因不能与工厂女郎一起工作。

更新2

我已经在以下位置提交了一份可能的错误报告:Their Github Repo

最佳答案

一般来说,Active Record 被设计为使用单表继承(同一张表用于所有子类的记录)而不是多表继承(子类使用不同的表。)

也就是说,您可以尝试覆盖 table_name 方法,而不是使用 self.table_name = 在您的子类中设置表名

def table_name
'xaaron_users'
end

看看这是否适用于您的场景。这是 mentioned as an alternative in the docs .

关于ruby-on-rails - Rails 不使用模型指定的表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28463305/

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