ruby - 在 Ruby 中，如果我在循环内声明一个 lambda 函数，它会在每次迭代后正确清理吗？

Question

我有这样的东西:

for i in 1..100000
    template = GetTemplate(i)

    set_setting_lam = lambda do |setting|
        (...) # Would prefer not to duplicate the code for the loops below
        template.setting = setting
    end

    for setting in settingArray
        set_setting_lam.call(setting)
    end

    for setting in settingList
        set_setting_lam.call(setting)
    end
end

这会生成 100000 个 set_setting_lam 对象，还是会在每次迭代后清除？

Answer 1

它会创建对象，并且不会在每次迭代后根据这个清理它们:

object_ids = []
1.upto(5) { |i| object_ids << lambda{ i }.object_id }
object_ids.each do |object_id|
  puts "#{ ObjectSpace._id2ref(object_id) } - #{ ObjectSpace._id2ref(object_id).call }"
end

#<Proc:0x007fae509c7380@test1.rb:2 (lambda)> - 1
#<Proc:0x007fae509c7330@test1.rb:2 (lambda)> - 2
#<Proc:0x007fae509c72e0@test1.rb:2 (lambda)> - 3
#<Proc:0x007fae509c7290@test1.rb:2 (lambda)> - 4
#<Proc:0x007fae509c7240@test1.rb:2 (lambda)> - 5

UPD

它会在一段时间后开始垃圾收集，对于我来说，1000 个对象 888 在循环结束后仍在内存中。