ruby - 检查范围集合中的整数

Question

我正在尝试找到确定给定整数在哪个范围内的最佳方法。以此哈希为例:

score_levels = {
  1 => {'name' => 'Beginner', 'range' => 0..50}, 
  2 => {'name' => 'Intermediate', 'range' => 51..70},
  3 => {'name' => 'Pro', 'range' => 71..85},
  4 => {'name' => 'Expert', 'range' => 86..96},
  5 => {'name' => 'Master', 'range' => 97..100}
}

我想在给定分数的情况下运行不同的逻辑，例如:

case score
when score_levels[1]['range']
  level_counters[1] += 1
when score_levels[2]['range']
  level_counters[2] += 1
when score_levels[3]['range']
  level_counters[3] += 1
end

有更通用的方法吗？也许本着这种精神:

score_levels.each |key, val| {if val['range'].member?(score) then level_counters[key] += 1 }

谢谢!

Answer 1

由于范围不重叠并无缝覆盖 0..100 - 您不需要明确的范围，而是像这样的东西:

score_levels = [
  {id:1, name: 'Beginner', max_score:50},
  {id:2, name: 'Intermediate', max_score:70},
  {id:3, name: 'Pro', max_score:85},
  {id:4, name: 'Expert', max_score:96},
  {id:5, name:  'Master', max_score:100}
].sort_by{|v| v[:max_score]}

sort_by 是可选的，但留在那里表示应该对数组进行排序

并找到自己(假设分数不超过最大值并且总能找到)

level_counters[ score_levels.find{|v| score <= v[:max_score]}[:id] ] += 1