ruby - 从 Ruby 中的数据中提取特定字段

Question

这是 Ruby 程序，我必须在其中使用正则表达式从文件中的数据中提取特定字段。文件中的数据格式如下:

11 月 13 日 01:46:57 10.232.47.76 qas-adaptiveip-10-232-47-76 2015-11-13 01:46:57 +0000 [信息]:qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d 已被注销

我需要提取以下值1)2015-11-13 01:46:57 +00002)qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d

我已经编写了代码，但它无法正常工作。有人可以帮我解决这个问题吗。

  class Task5
  def initialize
  #   @f=File.open('C:/Users/aroraku/Desktop,boc-adap_td-agent.log-2.log',r)
  @count=0
  end

  def check_line(line)
      if(line=~/deregistered adap_tdagt$/)
           line=~ (/.*(\d{4}-\d{2}-\d{2} \d{2}:\d{2}:\d{2} +\d{4})/)
               puts "#{$1}"
      end
  end

  def file_read
     open("boc-adap_td-agent.log-2.log") { |f|
          while line=f.gets do
             check_line(line)
          end
     }
    # return @count
  end
end

Answer 1

str = "Nov 13 01:46:57 10.232.47.76 qas-adaptiveip-10-232-47-76 2015-11-13 01:46:57 +0000 [info]: qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d has been deregistered adap_tdagt"

由于您的代码存在问题，我想建议另一种方法来从每一行中提取所需的信息:

r = /
    (?:                # begin a non-capture group
      \d{4}-\d{2}-\d{2}\s\d{2}:\d{2}:\d{2}\s\+\d{4} # match date string
    )                  # end non-capture group
    |                  # or
    (?:                # begin a non-capture group
      (?<=\[info\]:\s) # match "[info:] " in a positive lookbehind
      \S+              # match >= 1 characters other than whitespace
    )                  # end non-capture group
    /x                 # extended/free-spacing regex definition mode

str.scan(r)
  #=> ["2015-11-13 01:46:57 +0000", "qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d"]