ruby - 参数处理为 "rigid"是什么意思？

Question

取自documentation对于 Proc#lambda?:

Returns true for a Proc object for which argument handling is rigid. Such procs are typically generated by lambda.

什么是“刚性参数”处理？

Answer 1

如果传递了错误数量的参数，Lambdas 将引发一个 ArgumentError，而 Proc.new 则不会。

例子:

lam = ->(x){ "OK" }
lam.lambda? # => true
lam.call # => ArgumentError
lam.call(1) # => OK

proc = Proc.new { |x| "OK" }
proc.lambda? # => false
proc.call # => OK
proc.call(1) # => OK
proc.call(1,2,3,4,5,6,7,8,9) # => OK