Ruby 嵌套每个 do 循环

Question

我试图通过让这个程序运行来理解嵌套循环。如果可能的话，我想使用“每次做”的循环方式。现在循环执行所有第一个循环，然后是第二个……等等……我想做的是，执行第一个循环 1 次，然后下降到第二个循环一次……等等。这是我的代码(粘贴在下面)

期望的输出是这样的:

index                       3.0                  3.0
+-------------------------------------------------------+
0                          -23.4                -23.4
1                       -2226.74             -2226.74
2                   -1.93464e+07         -1.93464e+07

代码

class LogisticsFunction
  puts "Enter two numbers, both between 0 and 1 (example: .25 .55)."
  puts "After entering the two numbers tell us how many times you"
  puts "want the program to iterate the values (example: 1)."

  puts "Please enter the first number: "
  num1 = gets.chomp

  puts "Enter your second number: "
  num2 = gets.chomp

  puts "Enter the number of times you want the program to iterate: "
  iter = gets.chomp

  print "index".rjust(1)
  print num1.rjust(20)
  puts num2.rjust(30)
  puts "+-------------------------------------------------------+"

  (1..iter.to_i).each do |i|
    print i
  end
    (1..iter.to_i).each do |i|
      num1 = (3.9) * num1.to_f * (1-num1.to_f)
        print num1
    end
      (1..iter.to_i).each do |i|
        num2 = (3.9) * num2.to_f * (1-num2.to_f)
          print num2
      end
end

Answer 1

我认为你不必运行三个循环，下面会给出想要的输出

(1..iter.to_i).each do |i|
  print i
  num1 = (3.9) * num1.to_f * (1-num1.to_f)
  print num1.to_s.rjust(20)
  num2 = (3.9) * num2.to_f * (1-num2.to_f)
  print num2.to_s.rjust(30)
end