ruby - 将字符串数组分类为关闭正则表达式

Question

我有以下数组:

 a
=> ["http://dominio-1-736865.com/path1",
 "http://dominio-2-570941.com/path2",
 "http://102.160.194.146/path4",
 "http://142.231.2.110",
 "http://142.231.2.110/path/inventado",
 "http://dominio-3-468658.com/path2",
 "http://dominio-3-468658.com/path2/path1",
 "http://dominio-3-468658.com/path2/path2",
 "http://subdominio.dominio-3-468658.com/path2",
 "http://www.dominio-3-468658.com/path2",
 "http://este-se-repite.re/AP-448055"]

然后我需要这样分组:

fqdns
=> ["dominio-1-736865.com", "dominio-2-570941.com", "102.160.194.146", "142.231.2.110", "dominio-3-468658.com", "subdominio.dominio-3-468658.com", "este-se-repite.re"]

得到这个=

["http://dominio-1-736865.com/path1"]
["http://dominio-2-570941.com/path2"]
["http://102.160.194.146/path4"]
["http://142.231.2.110", "http://142.231.2.110/path/inventado"]
["http://dominio-3-468658.com/path2", "http://dominio-3-468658.com/path2/path1", "http://dominio-3-468658.com/path2/path2", "http://www.dominio-3-468658.com/path2"]
["http://subdominio.dominio-3-468658.com/path2"]
["http://este-se-repite.re/AP-448055"]

问题在于 subdominio.dominio-3-468658.com 和 dominio3-468658.com，它们可以分为两个，但我只需要在具有子域的那个中相遇。如何在 ruby​​ 中实现这一点

[25] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[1])}
=> [nil, #<MatchData "dominio-2-570941.com">, nil, nil, nil, nil, nil, nil, nil, nil, nil]
[26] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[0])}
=> [#<MatchData "dominio-1-736865.com">, nil, nil, nil, nil, nil, nil, nil, nil, nil, nil]
[27] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[2])}
=> [nil, nil, #<MatchData "102.160.194.146">, nil, nil, nil, nil, nil, nil, nil, nil]
[28] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[3])}
=> [nil, nil, nil, #<MatchData "142.231.2.110">, #<MatchData "142.231.2.110">, nil, nil, nil, nil, nil, nil]
[29] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[4])}
=> [nil, nil, nil, nil, nil, #<MatchData "dominio-3-468658.com">, #<MatchData "dominio-3-468658.com">, #<MatchData "dominio-3-468658.com">, #<MatchData "dominio-3-468658.com">, #<MatchData "dominio-3-468658.com">, nil]
[30] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[5])}
=> [nil, nil, nil, nil, nil, nil, nil, nil, #<MatchData "subdominio.dominio-3-468658.com">, nil, nil]
[31] pry(#<Notifications::Notification>)> a.map{|d| d.match(fqdns[6])}
=> [nil, nil, nil, nil, nil, nil, nil, nil, nil, nil, #<MatchData "este-se-repite.re">]

Answer 1

无需在此处添加正则表达式(并产生另一个问题)。使用正确的工具来完成工作:URI 解析器。

uris = ["http://dominio-1-736865.com/path1",
 "http://dominio-2-570941.com/path2",
 "http://102.160.194.146/path4",
 "http://142.231.2.110",
 "http://142.231.2.110/path/inventado",
 "http://dominio-3-468658.com/path2",
 "http://dominio-3-468658.com/path2/path1",
 "http://dominio-3-468658.com/path2/path2",
 "http://subdominio.dominio-3-468658.com/path2",
 "http://www.dominio-3-468658.com/path2",
 "http://este-se-repite.re/AP-448055"]

 require 'uri'

 uris.group_by{|u| URI(u).host}.values
 # => [
 #  ["http://dominio-1-736865.com/path1"], 
 #  ["http://dominio-2-570941.com/path2"], 
 #  ["http://102.160.194.146/path4"], 
 #  ["http://142.231.2.110", "http://142.231.2.110/path/inventado"], ["http://dominio-3-468658.com/path2", "http://dominio-3-468658.com/path2/path1", "http://dominio-3-468658.com/path2/path2"], 
 #  ["http://subdominio.dominio-3-468658.com/path2"], 
 #  ["http://www.dominio-3-468658.com/path2"], 
 #  ["http://este-se-repite.re/AP-448055"]
 #]

最后，如果您想要将域与“www”放在一起。与他们的裸体版本在同一个桶中:

uris.group_by{|u| URI(u).host.sub(/^www\./, '')}
=> {"dominio-1-736865.com"=>["http://dominio-1-736865.com/path1"],
 "dominio-2-570941.com"=>["http://dominio-2-570941.com/path2"],
 "102.160.194.146"=>["http://102.160.194.146/path4"],
 "142.231.2.110"=>["http://142.231.2.110", "http://142.231.2.110/path/inventado"],
 "dominio-3-468658.com"=>
  ["http://dominio-3-468658.com/path2", "http://dominio-3-468658.com/path2/path1", "http://dominio-3-468658.com/path2/path2", "http://www.dominio-3-468658.com/path2"],
 "subdominio.dominio-3-468658.com"=>["http://subdominio.dominio-3-468658.com/path2"],
 "este-se-repite.re"=>["http://este-se-repite.re/AP-448055"]}