arrays - 如何遍历哈希和数组并替换字符串中的单词

Question

我正在尝试遍历字符串数组并替换符合任何替换规则的单词:

array= ["I love chicken!", "I love lamb!", "I love beef!"]
substitutions = {
"love" => "hate",
"lamb" => "turkey"
}

我想遍历数组并检查与替换哈希中的键匹配的任何单词。该数组将变为:

array= ["I hate chicken!", "I hate turkey!", "I hate beef!"]

这是我目前所拥有的:

array.each do |strings|
strings = strings.split
    strings.each do |word|
        substitutions.each do |phrase,substitute|
            if word == phrase
                word = substitute
                return word
            end
        end
    end
end

Answer 1

这将为您提供所需的结果。如您所见，您有点过于复杂了

arry= ["I love chicken!", "I love lamb!", "I love beef!"]
substitutions = { "love" => "hate", "lamb" => "turkey" }

arry.each_with_index do |str,ind|
  substitutions.each_key do |word|
    arry[ind].gsub!(word,substitutions[word]) if str.include?(word)
  end
end

puts arry

这会给你:

[ "I hate chicken!", "I hate turkey!", "I hate beef!" ]

您拆分句子的策略行不通。感叹号会造成一些麻烦。在这种情况下，使用 #include? 进行测试的想法要好得多。

注意 gsub!(带有 !)的使用，这将对原始数组进行更改。