sql - 在 SQL 和 Sequel 中需要帮助，涉及内部连接和 where/filter

Question

需要帮助将sql传输到sequel:
查询语句:

SELECT table_t.curr_id FROM table_t
INNER JOIN table_c ON table_c.curr_id = table_t.curr_id 
INNER JOIN table_b ON table_b.bic = table_t.bic
WHERE table_c.alpha_id = 'XXX' AND table_b.name='Foo';

卡在续集里了，不知道怎么过滤，就这样了:

 cid= table_t.select(:curr_id).
                    join(:table_c, :curr_id=>:curr_id).
                    join(:table_b, :bic=>:bic).
                    filter( ????? )  

比上面更好的成语答案也很感激。Tnx。

更新:
我必须稍微修改一下才能让它工作

cid = DB[:table_t].select(:table_t__curr_id).
  join(:table_c, :curr_id=>:curr_id).
  join(:table_b, :bic=>:table_t__bic). #add table_t or else ERROR: column table_c.bic does not exist
  filter(:table_c__alpha_id => 'XXX',
         :table_b__name => 'Foo')

没有过滤器，

cid = DB[:table_t].select(:table_t__curr_id).
                    join(:table_c, :curr_id=>:curr_id, :alpha_id=>'XXX').
                    join(:table_b, :bic=>:table_t__bic, :name=>'Foo')

顺便说一句，我使用 pgsql 9.0

Answer 1

这是纯粹的续集方式:

cid = DB[:table_t].select(:table_t__curr_id).
  join(:table_c, :curr_id=>:curr_id).
  join(:table_b, :bic=>:bic).
  filter(:table_c__alpha_id => 'XXX',
         :table_b__name => 'Foo')

请注意，您也可以在没有 WHERE 的情况下执行此操作，因为您使用的是 INNER JOIN:

cid = DB[:table_t].select(:table_t__curr_id).
  join(:table_c, :curr_id=>:curr_id, :alpha_id=>'XXX').
  join(:table_b, :bic=>:bic, :name=>'Foo')