ruby - 将语素数组转换为 Ruby 中的句子

Question

我想转换由 PTB-style 生成的语素数组分词器:

["The", "house", "is", "n't", "on", "fire", "."]

一句话:

"The house isn't on fire."

实现此目标的明智方法是什么？

Answer 1

如果我们采纳@sawa 关于撇号的建议并将您的数组设为:

["The", "house", "isn't", "on", "fire", "."]

你可以得到你要找的东西(有标点符号支持!):

def sentence(array)
  str = ""
  array.each_with_index do |w, i|
    case w
    when '.', '!', '?' #Sentence enders, inserts a space too if there are more words.
      str << w
      str << ' ' unless(i == array.length-1)
    when ',', ';' #Inline separators
      str << w
      str << ' '
    when '--' #Dash
      str << ' -- '
    else #It's a word
      str << ' ' unless str[-1] == ' ' || str.length == 0
      str << w
    end
  end
  str
end