ruby - rake/Rspec : How to suppress/quiet/silent the first output line showing the command with --pattern ?

Question

问题:

如果我运行 ServerSpec (基于 RSpec )到 Rake使用以下命令之一:

• rake
• rake spec
• rake spec:all
• rake spec:<host>
• bundle exec rake
• ...

Rake 将它执行的命令打印到 stdout在 serverspec 输出之前:

/usr/bin/ruby1.9.1 
-I/var/lib/gems/1.9.1/gems/rspec-core-3.1.6/lib:/var/lib/gems/1.9.1/gems/rspec-support-3.1.2/lib 
/var/lib/gems/1.9.1/gems/rspec-core-3.1.6/exe/rspec 
--pattern spec/<host>/\*_spec.rb

如果我手动将目标主机传递给rspec像这样……

TARGET_HOST=<host> rspec

...该行不出现。

问题:

如何防止 Rake从输出这一行/命令？

---

我正在使用 serverspec-init 生成的默认 Rakefile .

require 'rake'
require 'rspec/core/rake_task'

task :spec    => 'spec:all'
task :default => :spec

namespace :spec do
  targets = []
  Dir.glob('./spec/*').each do |dir|
    next unless File.directory?(dir)
    targets << File.basename(dir)
  end

  task :all     => targets
  task :default => :all

  targets.each do |target|
    desc "Run serverspec tests to #{target}"
    RSpec::Core::RakeTask.new(target.to_sym) do |t|
      ENV['TARGET_HOST'] = target
      t.pattern = "spec/#{target}/*_spec.rb"
    end
  end
end

Answer 1

尝试改变

RSpec::Core::RakeTask.new(target.to_sym) do |t|
  ENV['TARGET_HOST'] = target
  t.pattern = "spec/#{target}/*_spec.rb"
end

到

RSpec::Core::RakeTask.new(target.to_sym) do |t|
  ENV['TARGET_HOST'] = target
  t.pattern = "spec/#{target}/*_spec.rb"
  t.verbose = false
end