ruby - 按包含值的长度对散列进行排序

Question

假设我有一个像这样的散列:

foo = {
  :bar => ['r', 'baz'], # has a total str length of 4 characters inside of the array
  :baz => ['words', 'etc', 'long words'] # has a total str length of 18 characters inside of the array,
  :blah => ['at'] # has a total str length of 2 characters inside of the array
  # etc...
}

我将如何根据数组中包含的项目的总字符串长度对这个散列进行排序？在这种情况下生成的哈希顺序应该是::blah, :bar, :baz

Answer 1

我会这样做:

Hash[foo.sort_by { |k, v| v.join.length }]

我假设您不打算更改原始哈希值，只是重新排序它们。