ruby - 如何拆分字符串并跳过空格？

Question

我有一个像 "This is a test " 这样的字符串。我想用空格字符拆分字符串。我这样做:

puts " This   is a test ".strip.each(' ') {|s| puts s.strip}

结果是:

This

is
a
test
This is a test

为什么最后一行“This is a test”？而且我需要，如果两个单词之间有两个或更多空格字符，则这不应返回“行”。

我只想在给定的字符串中拆分单词。
有人有想法吗？

Answer 1

irb(main):002:0> " This   is a test ".split
=> ["This", "is", "a", "test"]

irb(main):016:0* puts " This   is a test ".split
This
is
a
test

str.split(pattern=$;, [limit]) => anArray

If pattern is omitted, the value of $; is used. If $; is nil (which is the default), str is split on whitespace as if ` ’ were specified.