具有无限数量参数的 Ruby 函数

Question

如何创建没有明确参数数量的 Ruby 函数？

需要更多说明吗？

Answer 1

使用splat运算符*

def foo(a,b,c,*others)
   # this function has at least three arguments,
   # but might have more
   puts a
   puts b
   puts c
   puts others.join(',')
end
foo(1,2,3,4,5,6,7,8,9)
# prints:
# 1
# 2
# 3
# 4,5,6,7,8,9